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MySQL Group_concat结果IN给定数字

[英]MySQL Group_concat result IN given numbers

I'm trying to find out, if any number in a group_concat result is in a given set of numbers. 我试图找出是否group_concat结果中的任何数字在给定的数字集中。

This example data can be used to try it out: 此示例数据可用于尝试:

CREATE TABLE `events` (
  `eventid` int(11) NOT NULL AUTO_INCREMENT,
  `eventname` varchar(255) DEFAULT NULL,
  PRIMARY KEY (`eventid`)
) ENGINE=InnoDB AUTO_INCREMENT=2 DEFAULT CHARSET=latin1;

-- ----------------------------
--  Records of `events`
-- ----------------------------
BEGIN;
INSERT INTO `events` VALUES ('1', 'my event');
COMMIT;

-- ----------------------------
--  Table structure for `events2groups`
-- ----------------------------
CREATE TABLE `events2groups` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `eventid` int(11) DEFAULT NULL,
  `groupid` int(11) DEFAULT NULL,
  PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=4 DEFAULT CHARSET=latin1;

-- ----------------------------
--  Records of `events2groups`
-- ----------------------------
BEGIN;
INSERT INTO `events2groups` VALUES ('1', '1', '5'), ('2', '1', '3'), ('3', '1', '1');
COMMIT;

-- ----------------------------
--  Table structure for `groups`
-- ----------------------------
CREATE TABLE `groups` (
  `groupid` int(11) NOT NULL AUTO_INCREMENT,
  `groupname` varchar(255) DEFAULT NULL,
  PRIMARY KEY (`groupid`)
) ENGINE=InnoDB AUTO_INCREMENT=6 DEFAULT CHARSET=latin1;

-- ----------------------------
--  Records of `groups`
-- ----------------------------
BEGIN;
INSERT INTO `groups` VALUES ('1', 'group1'), ('2', 'group2'), ('3', 'group3'), ('4', 'group4'), ('5', 'group5');
COMMIT;

SET FOREIGN_KEY_CHECKS = 1;

Then fire this query: 然后触发此查询:

SELECT GROUP_CONCAT(groups.groupid), 
IF ( GROUP_CONCAT(groups.groupid) IN (1,2,3), 'yes', 'no' ) as isInGroup 
FROM `events`
LEFT JOIN events2groups ON events.eventid = events2groups.eventid
LEFT JOIN groups ON events2groups.groupid = groups.groupid
GROUP BY events.eventid

the first result column shows, that the event has the groups 5, 3 and 1. The user has the groups 1, 2 and 3, so the 3 and the 1 match. 第一个结果列显示事件具有组5、3和1。用户具有组1、2和3,因此3和1匹配。 How can I query this to get the 'yes' from the IF? 我该如何查询以从IF中获得“是”?

Why use the group_concat() results? 为什么要使用group_concat()结果? Just use conditional aggregation: 只需使用条件聚合:

SELECT GROUP_CONCAT(groups.groupid), 
       (case when max(groups.group_id in (1, 2, 3)) > 0 then 'yes' else 'no'
        end) as isInGroup 
FROM `events` LEFT JOIN
      events2groups
      ON events.eventid = events2groups.eventid LEFT JOIN
      groups
      ON events2groups.groupid = groups.groupid
GROUP BY events.eventid;
SELECT GROUP_CONCAT(groups.groupid), 
  GROUP_CONCAT(case when groups.groupid IN (1,2,3) then  'yes' else 'no' end) as isInGroup 
FROM `events`
LEFT JOIN events2groups ON events.eventid = events2groups.eventid
LEFT JOIN groups ON events2groups.groupid = groups.groupid
GROUP BY events.eventid
;

result no,yes,yes 结果不,是,是

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