按钮调用PHP以通过ID删除MySQL行

Question

Hi I have a html form button called delete. Next to the button is an input area. The logged in user will enter a number corresponding to the ID then press delete. It should delete the row corresponding to that ID.

For some reason it doesn't work.

This is my html form:

  <h3 class="block-head">Delete Job</h3>
<form action="deletejob.php" method="post" class="basic-grey">
<label>Please Enter Job ID</label><input type="text" name="idnum" id="id"/><br>

     <input type="submit" name="delete" value="delete"/>
</form>

This is my php code:

mysql_connect("********", "root", "******")
 or die("Connection Failed");
 mysql_select_db("jobslist")or die("Connection Failed");
 $idnum = $_POST['id'];
 $query = "delete from jobs_list where idnum = '".$id."'";
 if(mysql_query($query)){ echo "deleted";}
 else{ echo "fail";}

I know about switching to mysqli and that...I just want to see if this method works first.

thanks.

Answer 1

the name of your input is idnum yet you are looking in the $_POST array for id and in your query using the variable $id when you declare $idnum in the line previous.

$idnum = intval($_POST['idnum']);  
$query = "delete from jobs_list where idnum = '".$idnum."'";

Answer 2

PHP receive the data via $_POST as an array of input elements with the key as the NAME of the input field, so you have to change this line:

$idnum = $_POST['idnum'];

You can also change the input name and don't change the php code:

<input type="text" name="id" id="id"/>

It's a typical mistake, don't worry too much about that :P

Answer 3

您应该更改POST值。然后尝试

$idnum = $_POST['idnum']; 

Answer 4

Change the HTML, update the input type id to:

id="idnum"

then, update the PHP query while fetching the post value to:

$idnum = $_POST['idnum'];

It should work.