缩写IPv6地址

Question

There is an array with IP addresses. I need a selected IP address to shorten. For example:

['fcef:b0e7:7d20:0000:0000:0000:3b95:0565']

abbreviation rules: if a part beginning 0 need to del from part or there is eg 0000 need to change it to 0 . The previous example after abbreviation:

['fcef:b0e7:7d20:0:0:0:3b95:565']

Answer 1

You can use a generator expression within join as following :

>>> ':'.join('0' if i.count('0')==4 else i.lstrip('0') for i in s.split(':'))
'fcef:b0e7:7d20:0:0:0:3b95:565'

or as @JF Sebastian mentioned in comment you can just use i == '0000' instead of count !

>>> ':'.join('0' if i=='0000' else i.lstrip('0') for i in s.split(':'))
'fcef:b0e7:7d20:0:0:0:3b95:565'

Answer 2

You should use the ipaddress module from the standard library:

>>> import ipaddress
>>> str(ipaddress.ip_address('fcef:b0e7:7d20:0000:0000:0000:3b95:0565'))
'fcef:b0e7:7d20::3b95:565'
>>> ip = ipaddress.ip_address('fcef:b0e7:7d20:0000:0000:0000:3b95:0565')
>>> ip.compressed
'fcef:b0e7:7d20::3b95:565'
>>> ip.exploded
'fcef:b0e7:7d20:0000:0000:0000:3b95:0565'

---

This shortens the ip under the actual rules.

To shorten the ip with only the rule you cite, you can simply use replace :

>>> 'fcef:b0e7:7d20:0000:0000:0000:3b95:0565'.replace('0000', '0')
'fcef:b0e7:7d20:0:0:0:3b95:0565'