[英]How to read lines from a text file and store as char array?
I have an input text file with some instructions and, starting with line 7, several lines of text. 我有一个带有一些说明的输入文本文件,从第7行开始,有几行文本。 Something like this:
像这样:
hi gBroThuo oWdbmna eo mt ce oneain,nDustuh o n
Ade ds,bpopoonf oneigno abro wmt eIw
n,Yrtyt hlil t .s Ble a meyboefr rtIhoyod
wla rimw yidehl. kes ,oyn L af
fu;AcMadmdnae nddmh ita behsctr rft iHdo"l,sie g"hu!,n eoaecMBt-
- h
I need to store the text to be stored in a char
array (including the new line characters). 我需要将要存储的文本存储在
char
数组中(包括换行符)。 What functions can I used to read and store this text to a single char
array? 我可以使用哪些函数来读取此文本并将其存储到单个
char
数组中?
char fileBuf[MAXFILE];
FILE *f;
int c;
size_t i;
if (f = fopen("filename", "r")) {
for (i = 0; i < (MAXFILE - 1) && (c = getc(f)) != EOF; ++i)
fileBuf[i] = c;
fclose(f);
} else perror("Could not open file");
EDIT: you said you wanted to skip the first 7 lines. 编辑:您说您想跳过前7行。
int x;
char line[MAXLINE];
for (x = 0; x < 7; ++x)
fgets(line, MAXLINE, f); /* skips first 7 lines, so now file pointer
will point to data after the 7 lines */
You could do something like this: 您可以执行以下操作:
int i = 0;
while(fscanf(inputFile, %c, &charArray[i])!=EOF)
i++;
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