[英]Python: How to print only the actual value from a dictionary based on a specific key value?
I have a dictionary that is dynamically generated from the results of a Splunk search. 我有一本根据Splunk搜索结果动态生成的字典。 The content of the dictionary looks like this:
字典的内容如下所示:
SiteID Reporting Total
FLNGAASF1 3 9
MSNGAASF2 14 26
PANGAASF1 31 40
Here is my Python code that generates the dictionary: 这是我生成字典的Python代码:
SiteIDs = defaultdict(list)
SiteIDs.clear()
Splunk search goes here Splunk搜索在这里
for result in results.ResultsReader(jobC.results(segmentation='none')):
SiteID=result["SiteID"]
Reporting=result["Reporting"]
Total=result["Total"]
SiteIDs[SiteID].append(('Reporting',Reporting))
SiteIDs[SiteID].append(('Total',Total))
Now what I need to do is get the Reporting and Total numbers for specific SiteIDs. 现在,我需要获取特定SiteID的报告和总数。 For Example, suppose I want the Reporting and Total numbers for MSNGAASF2, so that I can print them in an HTML table as:
例如,假设我想要MSNGAASF2的报告号和总数,以便可以将它们打印在HTML表格中,如下所示:
14 / 26 14/26
or like this 或像这样
SiteID Clients
FLNGAASF1 0/9
MSNGAASF2 14/26
PANGAASF1 0/40
So I break out my dictionary entry like this: 所以我按如下方式分解字典条目:
Client=(SiteIDs['MSNGAASF2'])
Doing this: 这样做:
print Client,"<br />"
results in this: 结果:
[('Reporting', '14'), ('Total', '26')] [('Reporting','14'),('Total','26')]
If I try the replace function I get an error that replace is not a suported attribute in the list object. 如果尝试使用replace函数,则会收到一个错误,指出replace不是list对象中的支持属性。 No matter what I try I get an error stating that the attribute is not supported.
无论我尝试什么,都会收到一条错误消息,指出不支持该属性。
I've tried things like this but have had absolutely no luck. 我已经尝试过类似的事情,但是绝对没有运气。
print Client.get('MSNGAASF2ULLSA',0)," / ",Client.get('MSNGAASF2ULLSA',1)
and get this: 并得到这个:
print Client.get('MSNGAASF2',0)," / ",Client.get('MSNGAASF2',1) AttributeError: 'list' object has no attribute 'get' 打印Client.get('MSNGAASF2',0),“ /”,Client.get('MSNGAASF2',1)AttributeError:'list'对象没有属性'get'
All I want to do is print the values, and only the values, for the selected SiteID. 我要做的就是仅打印所选SiteID的值。 This can't be that hard but as a noob python developer I just can't seem to figure it out.
这不是那么难,但是作为一个noob python开发人员,我似乎无法弄清楚。
I need to do this because I have a second Splunk search that lists all SiteIDs and I need specific counts for each. 我需要这样做,因为我还有第二个Splunk搜索,其中列出了所有SiteID,并且我需要每个站点的特定计数。 Looping though the first Splunk search results takes forever.
尽管第一个Splunk搜索结果循环播放是永远的过程。 I'm hoping that using a dictionary will be significantly faster.
我希望使用字典会更快。
You are appending two separate tuples; 您要追加两个独立的元组; replace those two tuples with a new dictionary:
用新字典替换这两个元组:
for result in results.ResultsReader(jobC.results(segmentation='none')):
site_id = result["SiteID"]
reporting = result["Reporting"]
total = result["Total"]
SiteIDs[site_id].append({'Reporting': reporting, 'Total': total})
You could even just append the whole result
dictionary rather than extract two keys. 您甚至可以只附加整个
result
字典,而不必提取两个键。
You can then reference those keys in your code; 然后,您可以在代码中引用这些键。 each value in
SiteIDs
is a list, so you'd loop over the list to get at each individual dictionary: SiteIDs
中的每个值都是一个列表,因此您可以遍历该列表以获取每个单独的字典:
results = SiteIDs['MSNGAASF2']
for result in results:
print '<td> {Reporting} </td><td> {Total} </td>'.format(**result)
I used a str.format()
template here; 我在这里使用了
str.format()
模板 ; that allows you to use the keys in result
in the template to pull out specific values into a string. 允许您使用模板中的
result
中的键将特定值提取到字符串中。
Now, if your SiteID
values in the Splunk result set are always going to be unique, then using a defaultdict(list)
is overkill; 现在,如果您在Splunk结果集中的
SiteID
值始终是唯一的,那么使用defaultdict(list)
会过大。 you could just use a regular dictionary and just store the result dictionary per SiteID
in there: 您可以只使用常规字典,并仅在其中存储每个
SiteID
的结果字典:
for result in results.ResultsReader(jobC.results(segmentation='none')):
SiteIDs[result["SiteID"]] = result
then forgo the loop per id: 然后放弃每个ID的循环:
result = SiteIDs['MSNGAASF2']
print '<td> {Reporting} </td><td> {Total} </td>'.format(**result)
the default dictionary makes a dictionary of lists. 默认字典构成列表字典。 if you want a true dictionary you should structure it like so:
如果您想要一本真正的字典,则应该像这样构造它:
mydict = {'FLNGAASF1': {'Reporting': 3, 'Total': 9}}
you could also go: 您也可以去:
mydict['FLNGAASF1'] = {'Reporting': 3, 'Total': 9}
then to retrieve the data: 然后检索数据:
print(mydict['FLNGAASF1'])
>>> {'Reporting': 3, 'Total': 9}
full example (assuming your splunk search results is iterable): 完整的示例(假设您不满意的搜索结果是可迭代的):
mydict = {}
for row in splunk:
mydict[row['SiteID']] = {'Reporting': row['Reporting'], 'Total': row['Total']
then just print your print your values: 然后只需打印您的值即可:
for k, v in mydict.items():
print("Client: %s: %d/%d" % (k, v['Reporting'], v['Total']))
>>>Client: FLNGAASF1: 3/9
>>>Client: MSNGAASF2: 14/26
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