[英]Ruby on Rails - conditional statement
I have the following method 我有以下方法
def providers
if super.present?
super.map(&:name).join("#{I18n.t('healtherecord_engine.shared.provider_name_separator')}<br>").html_safe
else
I18n.t('healtherecord_engine.data.no_data')
end
end
The provider has the following model schema 提供者具有以下模型架构
"providers": [
{
"name": "",
"relationship": ""
}
],
The problem is, when the provider has a blank "name" and has a "relationship", it displays "nothing" - just a blank. 问题是,当提供程序的“名称”为空白并且“关系”为空时,它显示“无”-仅是空白。 I still want it to display a "--"(I18n.t('healtherecord_engine.data.no_data')).
我仍然希望它显示一个“-”(I18n.t('healtherecord_engine.data.no_data'))。
I tried doing this, 我尝试这样做
def providers
names = super.map(&:name).join("#{I18n.t('healtherecord_engine.shared.provider_name_separator')}<br>")
names.present? ? names.html_safe : I18n.t('healtherecord_engine.data.no_data')
end
Still no luck. 仍然没有运气。 What am I doing wrong here?
我在这里做错了什么? Can anyone show me some direction with this?
谁能告诉我一些指导吗? Thank you in advance
先感谢您
To avoid confusion, I18n.t('healtherecord_engine.shared.provider_name_separator') = "," I18n.t('healtherecord_engine.data.no_data') = "--" 为避免混淆,I18n.t('healtherecord_engine.shared.provider_name_separator')=“,” I18n.t('healtherecord_engine.data.no_data')=“-”
Change: 更改:
if super.present?
to 至
if super && super.any?(&:name)
Also note that calling super multiple times might be dangerous: 另请注意,多次调用超级可能很危险:
prov_hash = super
if prov_hash && prov_hash.any?(&:name)
Quite likely it can be further optimized, but this depends on the super method. 它很有可能可以进一步优化,但这取决于超级方法。
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