[英]unexpectedly found nil while unwrapping an Optional value - Using ALAMOFIRE
I am trying to use Alamofire for GETs in JSON. 我试图在JSON中使用Alamofire进行GET。 When I use one URL - It works fine and when I use another I get an error unwrapping an optional value. 当我使用一个URL - 它工作正常,当我使用另一个时,我得到一个错误解开一个可选值。 I cannot seem to track where the error is coming from. 我似乎无法追踪错误的来源。 I have resorted in putting the code in ViewDidLoad to track the error. 我已经将代码放在ViewDidLoad中来跟踪错误。 I don't know if its the recipient and they want some sort of authorisation. 我不知道它是否是收件人,他们想要某种授权。 but I know its not the println's cos when i // them - it still comes up as an error , heres the code : 但我知道它不是println的cos当我//他们 - 它仍然出现错误,继承代码:
request(.GET, "https://api.doingdata.net/sms/send?api_service_key='APIKey'&msg_senderid=Edify-FYI&msg_to=&msg_text={otp|Edify-FYI|3600|ETEN|4} &msg_clientref=abcdef123456&msg_dr=0&output=json")
.validate()
.responseJSON { (_, _, _, error) in
println(error)
}
but I use : 但我用:
request(.GET, "http://httpbin.org/")
.validate()
.responseJSON { (_, _, _, error) in
println(error)
}
it works fine and returns nil for the error. 它工作正常并返回错误的nil。
Any help would be great, as its driving me nuts. 任何帮助都会很棒,因为它让我疯狂。
The reason is simple: your URL has special characters. 原因很简单:您的URL有特殊字符。 So, if you do 所以,如果你这样做
let url = NSURL(string:yourURLString) //returns nil
It will return nil. 它将返回零。 You would need to format your URL to be suitable for making requests. 您需要将URL格式化为适合发出请求。 Here is one solution for you. 这是一个适合您的解决方案。
var urlString = "https://api.doingdata.net/sms/send?api_service_key='APIKey'&msg_senderid=Edify-FYI&msg_to=&msg_text={otp|Edify-FYI|3600|ETEN|4} &msg_clientref=abcdef123456&msg_dr=0&output=json"
urlString = urlString.stringByAddingPercentEncodingWithAllowedCharacters(NSCharacterSet.URLQueryAllowedCharacterSet())!
request(.GET, urlString, parameters: nil, encoding: .JSON)
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