在PHP中“退出”脚本的正确方法

Question

I have a static method named ServerResponse that basically shows a message whether on success or fail. I just want to know the proper way to actually display the message and exit the script.

Should I implement my method like this:

public static function ServerResponse($e,$m){

    print(json_encode([$e,$m]));
    exit;
}

//Sample use:

if(this happens){
    myclass::ServerResponse($x,$y);
}

or like this:

public static function ServerResponse($e,$m){
    return json_encode([$e,$m]);
}

//Sample use:

if(this happens){
    print(myclass::ServerResponse($x,$y));
    exit;
}

• Which one is proper and better... and why?
• is there any difference between them? (on execution time).

"Don't be hard on me I am not an expert (just yet)..."

Answer 1

For better debugging, it's advised to always make a function or method return a value. So your 2nd sample should be chosen.

exit (or die ) are commonly used when the program ends with an error, giving the ability to add an exit status (as a number or a string).

I suppose there will be no significant difference about the execution time.

Answer 2

I don't know if this is common practice but I only use exit to debug. If your script comes to the end of execution it will exit on it's own.

If you must exit, do it in the main script, not in a function. functions should have one task and do that task. So the function ServerResponse should send a response and not kill the script.