PHP-将函数参数强制为整数

Question

In PHP you can do the following thing:

class Something {// bla bla}

function functionName(Something $object) {
    // Do stuff here  ^^^^^^^^^
}

This ensures that function received an instance of Something class.

My problem is that I want to enforce to a basic type.

function functionName(integer $someInt) {
    // Do stuff here  ^^^^^^^
}
functionName(5);

This says that $someInt is "not an instance of integer, integer given" (with my PHP version below 7.0). How can you enforce to a basic type?

Answer 1

You can't do this for scalar types see the manual:

And a quote from there:

Type hints cannot be used with scalar types such as int or string . Resources and Traits are not allowed either.

But you will be able to to this with PHP 7: https://wiki.php.net/rfc/scalar_type_hints_v5

Answer 2

You can't typehint scalar types in PHP. The only chance is to use a wrapper type. The SPL library ships with SplInt for that purpose.

Update: Looks like PHP 7 offers that feature. Sigh, times changed :)