在PHP中解析CSV的正则表达式

Question

I already managed to split the CSV file using this regex: "/,(?=(?:[^\\"] \\"[^\\"] \\") (?![^\\"] \\"))/"

But I ended up with an array of strings that contain the opening and ending double quotes. Now I need a regex that would strip those strings of the delimiter double quotes.

As far as I know the CSV format can encapsulate strings in double quotes, and all the double quotes that are already a part of the string are doubled. For example:

My "other" cat

becomes

"My ""other"" cat"

What I basically need is a regex that will replace all sequences of N doublequotes with a sequence of (N/2 - rounded down) double quotes.

Or is there a better way ? Thanks in advance.

Answer 1

有读取csv文件的功能： fgetcsv

Answer 2

Why do you bother splitting the file with regex when there's fgetcsv function that does all the hard work for you?

You can pass in the separator and delimiter and it will detect what to do.

Answer 3

For those of you who wan't to use regex instead of fgetcsv. Here is a complete example how to create a html table from csv using a regex.

    $data = file_get_contents('test.csv');
    $pieces = explode("\n", $data);

    $html .= "<table border='1'>\n";
    foreach (array_filter($pieces) as $line) {

            $html .= "<tr>\n";
            $keywords = preg_split('/,(?=(?:[^\"]*\"[^\"]*\")*(?![^\"]*\"))/', $line,-1,PREG_SPLIT_DELIM_CAPTURE);

            foreach ($keywords as $col) {
                    $html .= "<td>".trim($col, '"')."</td>\n";
            }
            $html .= "</tr>\n";
    }
    $html .= "</table>\n";

Answer 4

I agree with the others who said you should use the fgetcsv function instead of regexes. A regex may work okay on well-formed CSV data, but if the CSV is malformed or corrupt, the regex will silently fail, probably returning bogus results in the process.

However, the question was specifically about stripping unwanted quotation marks after the initial split. The one proposed solution (so far) is too naive, and it only deals the escaped quotes inside a field, not the actual delimiters. (I know the OP didn't ask about those, but they do need to be removed, so why not do them at the same as the others?) Here's my solution:

$csv_field = preg_replace('/"(.|$)/', '\1', $csv_field);

This regex matches a quotation mark followed by any character or by the end of the string, and replaces the matched character(s) with the second character, or with the empty string if it was the $ that matched. According to the spec, CSV fields can contain line separators; that doesn't seem to happen much, but you can add the 's' modifier to the regex if you need to.

Answer 5

preg_split('/,(?=(?:[^\"]*\"[^\"]*\")*(?![^\"]*\"))/', $line,-1,PREG_SPLIT_DELIM_CAPTURE);

Has Problems with " inside of strings like "Toys"R"Us"

So u should use instead:

preg_split('/'.$seperator.'(?=(?:[^\"])*(?![^\"]))/', $line,-1, PREG_SPLIT_DELIM_CAPTURE);

Answer 6

这是我的快速尝试，尽管它仅适用于单词边界。

preg_replace('/([\W]){2}\b/', '\1', $csv)