在java中的特定单词之后或之前删除部分字符串

Question

Is there a command in java to remove the rest of the string after or before a certain word;

Example:

Remove substring before the word "taken"

before: "I need this words removed taken please"

after:

"taken please"

Answer 1

String are immutable, you can however find the word and create a substring :

public static String removeTillWord(String input, String word) {
    return input.substring(input.indexOf(word));
}

removeTillWord("I need this words removed taken please", "taken");

Answer 2

There is apache-commons-lang class StringUtils that contains exactly you want:

eg public static String substringBefore(String str, String separator)

Answer 3

public static String foo(String str, String remove) {
     return str.substring(str.indexOf(remove));
}

Answer 4

Clean way to safely remove until a string

String input = "I need this words removed taken please";
String token = "taken";
String result = input.contains(token)
  ? token + StringUtils.substringAfter(string, token)
  : input;

Apache StringUtils functions are null-, empty-, and no match- safe

Answer 5

Since OP provided clear requirements

Remove the rest of the string after or before a certain word

and nobody has fulfilled those yet, here is my approach to the problem. There are certain rules to the implementation, but overall it should satisfy OP's needs, if he or she comes to revisit the question.

public static String remove(String input, String separator, boolean before) {
  Objects.requireNonNull(input);
  Objects.requireNonNull(separator);

  if (input.trim().equals(separator)) {
    return separator;
  }

  if (separator.isEmpty() || input.trim().isEmpty()) {
    return input;
  }

  String[] tokens = input.split(separator);

  String target;
  if (before) {
    target = tokens[0];
  } else {
    target = tokens[1];
  }

  return input.replace(target, "");
}