按某些列过滤文本文件行，不带引号

Question

so I have a file that I'd like to only get certain rows from, but unfortunately the strings within those rows aren't surrounded by quotation marks. How can I filter these rows based on the 2nd column value?? Eg I have:

string a,string b,string c,string d,string e
string 1,string 2,string 3,string 4,string 5
string f,string b,string h,string i,string j
string 6,string 7,string 8,string 9,string 0

And I want in a new file only:

string a,string b,string c,string d,string e
string f,string b,string h,string i,string j

I'm trying to use the command:

awk -F '","'  'BEGIN {OFS=","} { if (toupper($2) == "STRING B")  print }' input.csv > output.csv

Answer 1

Your code should work if you use -F, instead of -F '","' . A somewhat more idiomatic way to do the same is

awk -F, -v OFS=, 'toupper($2) == "STRING B"' input.csv

In awk code, a condition without an associated action means to perform the default action (printing) if the condition is true, so this comes to the same effect with less fluff.

Answer 2

You don't need to include double quotes on setting the FS value.

$ awk -F,  'BEGIN {OFS=","} { if (toupper($2) == "STRING B")  print }' file
string a,string b,string c,string d,string e
string f,string b,string h,string i,string j