[英]JavaScript Unshift EACH array element
I have two arrays that contain objects.我有两个包含对象的数组。
arr1
and arr2
. arr1
和arr2
。 If I unshift arr1
to contain the elements of arr2
, the elements are not appended individually into arr1
, instead the whole array ( arr2
) is appended at the beginning, for example:如果我取消移动
arr1
以包含arr2
的元素,则元素不会单独附加到arr1
,而是将整个数组 ( arr2
) 附加到开头,例如:
arr1 = [{ele:1}, {ele:2}]
arr2 = [{ele:3}, {ele:4}]
I get: arr1 = [[{ele:3}, {ele:4}], {ele:1}, {ele:2}]
我得到:
arr1 = [[{ele:3}, {ele:4}], {ele:1}, {ele:2}]
Notice the whole array inside instead of its objects.注意里面的整个数组而不是它的对象。
I want: arr1 = [{ele:3}, {ele:4}, {ele:1}, {ele:2}]
我想要:
arr1 = [{ele:3}, {ele:4}, {ele:1}, {ele:2}]
My arrays are ko.observableArray(), maybe that makes a difference?我的数组是 ko.observableArray(),也许这有区别?
你去吧:
[].unshift.apply(arr1, arr2);
maybe this might be bit simpler也许这可能更简单一些
let arr1 = [{ ele: 1 }, { ele: 2 }];
let arr2 = [{ ele: 3 }, { ele: 4 }];
for (const iterator of arr2) {
arr1.unshift(iterator);
}
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