JPA标准查询中的JPA 2.0子选择

Question

How to write criteria query with subquery (use CriteriaBuilder construct method)?

  select t1.id,
       t1.name,
       (select count(t2.id) from table_name_2 t2 where t2.t1_id = t1.id) as   some_count
    from table_name t1

Thank in advance

Answer 1

编写方法相同，但使用实体类名称代替table_name。