python错误：无法分配给函数调用

Question

This may be a stupid question, Why do i get this error? when I chane int(r) into r, it makes TypeError"unsupported operand type(s) for - 'str' and 'int'" I want to make the program that compare the YOURNUMBER with random number and repeat "n" times. How can I solve this problem?

import random
r = raw_input("put YOURNUMBER")
while True: 
    n = raw_input("put repetition number")
    int(r)= int(r) - 1
    for x in range(10):
        x = random.randit()
    if int(r)!= 0:
        if int(n) > int(x):
            print "n > x"
        if float(n) == float(x):
            print "n = x"
        if float(n) < float(x):
            print "n < x"
    else:
        break
print "The end"

Answer 1

Convert r to an integer before entering the while loop. Similarly convert n to an integer when it is input. Also it should be random.randint() , not random.randit() - and it requires some arguments for the range of values:

import random
r = int(raw_input("put YOURNUMBER"))
while True: 
    n = int(raw_input("put repetition number"))
    r = r - 1
    for x in range(10):
        x = random.randint(1, 10)
    if r != 0:
        if int(n) > int(x):
            print "n > x"
        if float(n) == float(x):
            print "n = x"
        if float(n) < float(x):
            print "n < x"
    else:
        break
print "The end"

Answer 2

If I understand you correctly:

import random

r = raw_input("put YOURNUMBER: ")
r = int(r)


while True:
    n = raw_input("put repetition number: ")
    n = int(n)

    if n == 0:
        break

    for _ in xrange(n):
        x = random.randint(1, 10)

        if r > x:
            print "%s > %s" % (r, x)
        if r == x:
            print "%s = %s" % (r, x)
        if r < x:
            print "%s < %s" % (r, x)

print "The end"

Every variable has a type. Function raw_input returns a string, that's why r and n are strings firstly. Function int() converts variable into integer. After your converting into integer you don't need to use int() for r and n again