最终静态方法和变量在Java中的存储方式和位置？

Question

class X
{

final static void show()
{

  System.out.println("Show");

}
}
class Y extends X
{

  public static void main(String s[])
  {
     new Y().show();
  }
}

Where and how is memory allocated to final static methods, and how are they accessed?

Answer 1

When you make a static method final, its hidden in the inheriting class. You can find a decent explanation at http://www.coderanch.com/how-to/java/OverridingVsHiding

Answer 2

When you create a method with the modifier "final" you are modifying that method so that it cannot be overridden or hidden.

So if you were for some reason to create another class that were to extend your class X (which is known as inheritance), you would not be allowed to modify, or override your show() method. Furthermore, any other class would be able to access that method.

If you want a more in depth explanation, I suggest reading the Java API: https://docs.oracle.com/javase/specs/jls/se7/html/jls-8.html