Python-如果或无效语法错误

Question

I have the following line of code in Python:

if (sheet1.cell_value(i,8).lower()==sheet2.cell_value(0,j).lower() or (if hasattr(sheet2.cell_value(2,j), 'lower'): if sheet1.cell_value(i,8).lower()==sheet2.cell_value(2,j).lower())):

I currently get a SyntaxError: invalid syntax error

The reason I try to use this or , if statements is that sheet2.cell_value(2,j) may not have a value in Excel (in which case it would be #VALUE! ) in Excel. Thus, the second if in the or sheet1.cell_value(i,8).lower()==sheet2.cell_value(2,j).lower())): must be evaluated only in case there is a value in the cell.. How can I fix that? Thanks

Answer 1

First, a little bit of formatting wouldn't hurt. You don't have to smash your if statement onto one line. Additionally, the way you have it now is invalid. Break your if s onto separate lines

Second, you have parenthesis issues. Currently, the parenthesis are going across statements (through the colon).

This block aligns the parenthesis. I removed the ones surrounding the entire statement. Instead, we have your first or conditional. If that evaluates to True , then we do your second equality check. If that passes, the rest of your logic goes into that block.

if sheet1.cell_value(i,8).lower()==sheet2.cell_value(0,j).lower() or  hasattr(sheet2.cell_value(2,j), 'lower'): 
    if sheet1.cell_value(i,8).lower()==sheet2.cell_value(2,j).lower():
        # Do stuff here

Answer 2

Writing (if ...) or if ...: if ... are both forbidden in Python. If you want to write "condition1, and, if that's true, also condition2", just write condition1 and condition2 (in which case condition2 will not be evaluated if condition1 is false). Thus:

if (sheet1.cell_value(i,8).lower()==sheet2.cell_value(0,j).lower() or (hasattr(sheet2.cell_value(2,j), 'lower') and sheet1.cell_value(i,8).lower()==sheet2.cell_value(2,j).lower())):