php代码以数据透视表格式显示数据

Question

My Database has data like below..

surveyorname       bookingdate       receiptno
  raj              20-03-2015         56   
  raj              20-03-2015         701 
  angel            21-03-2015         55    
  raj              22-03-2015         700

Now My Code display data like below format..

surveyorname         20-03-2015
   raj                  2
  21-03-2015            --
   angel                1
  22-03-2015            --
   raj                  1

I need to display Report format like below...

 surveyorname    20-03-2015        21-03-2015        22-03-2015  
    raj             2                                    1
    angel                            1

My query getting data properly but only thing is I cannot understand how to display this in above format...

   <?php
$book = $database->getRows("SELECT surveyor_name as srv, bookingdate as bd, COUNT(DISTINCT receipt_no) as num  FROM receipt_entry  GROUP BY surveyor_name, bookingdate");
$days=array();
$line=array();
foreach ($book as $b) {
   $days[$d['bd']]=1;
   if (!is_array($line[$d['srv']])) {
      $line[$d['srv']]=array();
   }
   $line[$d['srv']][$d['bd']]=$d['num'];
}
print "<table><tr><th></th>\n";
foreach ($days as $d=>$n) {
      print "<th>$d</th>\n";
}
print "</tr>\n";
foreach ($line as $srv=>$l) {
    print "<tr><td>$srv</td>";
    foreach ($days as $d=>$n) {
        print "<td>" . $l[$d] . "</td>\n";
    }
    print "</tr>\n";
} 
print "</table>\n";
?>

Answer 1

可以试试这个

SELECT count(*) as TotalNum, surveyorname, bookingdate FROM your_table group by bookingdate,surveyorname;

Answer 2

$book = $database->getRows("SELECT surveyor_name as srv
   , booking_date as bd
   , COUNT(*) as num 
   FROM receipt_entry 
   GROUP BY surveyor_name, booking_date 
   ORDER BY booking_date");

$days=array();
$line=array();
foreach ($book as $b) {
   $days[$d['bd']]=1;
   if (!is_array($line[$d['srv']])) {
      $line[$d['srv']]=array();
   }
   $line[$d['srv']][$d['bd']]=$d['num'];
}
print "<table><tr><th></th>\n";
foreach ($days as $d=>$n) {
      print "<th>$d</th>\n";
}
print "</tr>\n";
foreach ($line as $srv=>$l) {
    print "<tr><td>$srv</td>";
    foreach ($days as $d=>$n) {
        print "<td>" . $l[$d] . "</td>\n";
    }
    print "</tr>\n";
} 
print "</table>\n";