修改数组perl中的多个元素

Question

Say I were to have a file with a name field and 3 date fields and wanted to reformat the dates. I could go like this:

while (<DATA>) {
  my @lines = split(/\|/); ##splitting DATA by '|'

  my @dates = split( /\/|[-]/, $lines[0] ); #splitting only the first element of array and performing modifications below.
  if ( $dates[2] =~ /^[0-1][0-9]$/gi ) { $dates[2] = $dates[2] + 2000 }
  elsif ( $dates[2] =~ /^[2-9][0-9]$/gi ) {
    $dates[2] = $dates[2] + 1900;
  }
  if ( $dates[1] =~ /^\d$/gi ) { $dates[1] = "0" . $dates[1] }
  if ( $dates[0] =~ /^\d$/gi ) { $dates[0] = "0" . $dates[0] }
  my $date = join "-", @dates[ 2, 0, 1 ]; #joining the dates to be in yyyy-mm-dd format.
  print $date, "\n"; #double check
  print $date, ",", ( join ",", @lines[ 1 .. $#lines ] ), "\n"; appending date to print the join of @lines.
}

Instead of having to split and join each $line[0] through $lines[2], is there a way to perform the modifications on all of the deisired fields at once? ($lines[0] through $lines[2]).

__DATA__
12/23/2014|2/20/1995|3/25/1905|josh

Answer 1

Your script gives nasty output with the input you provided. The output of the following seems much more logical to me:

#!/usr/bin/env perl

use strict;
use warnings;

while (my $line = <DATA>) {
    next unless $line =~ /\S/;
    my ($name, @dates) = reverse split qr{\|}, $line;
    @dates = reverse map sprintf('%04d-%02d-%02d', (split qr{/})[2,0,1]), @dates;
    print join(',', @dates, $name), "\n";
}
__DATA__
12/23/2014|2/20/1995|3/25/1905|josh

Output:

2014-12-23,1995-02-20,1905-03-25,josh

If this not the output you want then describe the exact output you are trying to get.

A few points:

• while (<DATA>) reads a single line from DATA . Assign it to a meaningful variable to make your code easier to read.

• Skip processing on empty lines

• Don't fall victim to LTS : /\\|/ is much harder to distinguish than qr{\\|} or even qr{ \\| }x qr{ \\| }x .

• The reverse s make the code easier to read, but if you have a ton of fields, they may become a real bottleneck. In that case, pop and push .

Answer 2

You can use regular expressions to help match your data line various bits and pieces and do away with the multiple splits. Using regular expressions can also verify your line format. Do you have a 3 digit month? Do you have three dates? It's always a good idea to verify your input:

#! /usr/bin/env perl
#
use strict;
use warnings;
use feature qw(say);

my $date_re = qr(
        ^(?<month1>\d{1,2})/
        (?<day1>\d{1,2})/
        (?<year1>\d{2,4})
        \|                    # Separator between date1 and date2
        (?<month2>\d{1,2})/
        (?<day2>\d{1,2})/
        (?<year2>\d{2,4})
        \|                    # Separator between date2 and date3
        (?<month3>\d{1,2})/
        (?<day3>\d{1,2})/
        (?<year3>\d{2,4})
        \|                    # Separator between date3 and name
        (?<name>.*)
    )x;
while ( my $line = <DATA> ) {
    my @array;
    if ( not @array = $line =~ m^$date_re^ ) {
        say "Something's wrong";
    }
    else {
        say "First Date: Year = $+{year1}  Month = $+{month1}  Day = $+{day1}";
        say "Second Date: Year = $+{year2}  Month = $+{month2}  Day = $+{day2}";
        say "Third Date: Year = $+{year3}  Month = $+{month3}  Day = $+{day3}";
        say "Name = $+{name}";
    }
}

__DATA__
12/23/2014|2/20/1995|3/25/1905|josh

Running this program prints out:

First Date: Year = 2014  Month = 12  Day = 23
Second Date: Year = 1995  Month = 2  Day = 20
Third Date: Year = 1905  Month = 3  Day = 25
Name = josh

This is using some advanced features of regular expressions:

• qr/.../ can be used to define regular expressions. Since you have slashes in the regular expression, I decided to use parentheses to delimit my regular expression, so it's qr(...) .

• The )x at the end means I can use white space to make my regular expression easier to understand. For example, I broke out each of the dates onto three lines (month, day, year).

• (?<name>...) names your capture group which makes it easier to refer back to a particular capture group. I can use the %+ hash to recall my capture groups. For example (?<month1>\\d{1,2}) says that I expect a 1 to two digit month. I store this in the capture group month1 , and I can refer back to this by using $+{month1} .

  One of the nice things about using named capture groups is that it documents what you're attempting to capture.

• The {M,N} is a repeat. I expect the previous regular expression to happen from M to N times. \\d{1,2} means I'm expecting one or two digits.

Answer 3

You have to keep the spliting of the fields and the join, but you may reduce the substitutions to:

$dates[2] =~ s/^([01]\d)$/20$1/;
$dates[2] =~ s/^([2-9]\d)$/19$1/;
$dates[1] =~ s/^(\d)$/0$1/;
$dates[0] =~ s/^(\d)$/0$1/;

Answer 4

It's ugly, but it does it all the fields in one pass as you requested.

while (<DATA>) {
    s/
      (?:^|\|)\K # start after a leading start-of-line or pipe
      (\d{1,2})
      [\/-]
      (\d{1,2})
      [\/-]
      (\d\d(?:\d\d)?)
      (?=\||\z) # look-ahead to see trailing pipe or end-of-string
     /
        sprintf('%04d-%02d-%02d',
            $3 <  20 ? $3 + 2000
          : $3 < 100 ? $3 + 1900
          : $3,
            $1,
            $2
        )
     /gex;
    print;

}

__DATA__
1/23/14|2/20/95|3/25/1905|josh