mysql_connect（）使用什么密码和用户名？
[英]What password and username do I use for mysql_connect()?
问题描述
Okay so as you will probably be able to tell but, I am pretty new to MySQL and PHP and I have ran into a problem.. In my connect.php , which connects to the server, I don't know if my password and username along with the port are right. 
好的，您可能会知道，但是，我对MySQL和PHP还是很connect.php ，并且遇到了问题。在连接到服务器的connect.php ，我不知道我的密码和用户名和端口是正确的。 Now the reason it says port 8080 is because one of my other web development programs was using port 80 so I went in to the Apache files and changed to port, so now when I log into phpMyAdmin I have to type localhost:8080 . 现在它说端口8080的原因是因为我的其他Web开发程序之一正在使用端口80，所以我进入了Apache文件并更改为端口，所以现在当我登录phpMyAdmin时，必须键入localhost:8080 。 I don't know if that has to do with mysql_connect , also I checked on phpMyAdmin and it says my username is root and my password is empty. 我不知道这是否与mysql_connect ，我也检查了phpMyAdmin，它说我的用户名是root ，密码是空的。 Does the empty password mess with MySQL_connect() ? 空密码是否与MySQL_connect() ？ Thanks, here's the code: 谢谢，这是代码：
connect.php : connect.php ：
<?php
//This file allows me to easily connect to my database
mysql_connect("localhost:8080", "root", "");//connects to database, params are ("servername", "username", "password");
mysql_select_db("membersystem");//selects the table from db
?>
login.php : login.php ：
<?php
error_reporting (E_ALL ^ E_NOTICE);//saves us from getting undefined index error
session_start();//makes it a sesion based system
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Login</title>
</head>
<body>
<!--the action='./login.php' tells the page where its gonna send the info, and the method='post' makes it so it dosent show the users personal info -->
<?php
$form = "<form action='./login.php' method='post'>
<table>
<tr>
<td>Username</td>
<td><input type='text' name='user'/></td>
</tr>
<tr>
<td>Password</td>
<td><input type='password' name='password'/></td>
</tr>
<tr>
<td></td>
<td><input type='submit' name='loginbtn' value='Login'/></td>
</tr>
</table>
</form>";
if($_POST['loginbtn']){//if loginbtn pressed
$user = $_POST['user'];//gets the username from text field from the form above
$password = $_POST['password'];//gets the password from text field from the form above
if($user){//checks if the username field from the form has been filled out
if($password){//checks if the password field from the form has been filled out
require("connect.php");//connects to db through connect.php
$password = md5(md5("gshgrYY665f".$password."gr76TH967G"));//encrypts the password
//echo "$password"; echos the hash for password (5f8b1a8d8f2471a2c7c17e0058873447 )
$query = mysql_query("SELECT * FROM users WHERE username='$user' ");//checks if the username is found in database
$numrows = mysql_num_rows($query);
if($numrows == 1){
$row = mysql_fetch_assoc($query);//gets the query associated with the php
$dbid = $row['id'];//gets the id from db
$dbuser = $row['username'];//gets the username from db
$dbpass = $row['password'];//gets the password from db
$dbactive= $row['active'];//gets the active value from db
if($password == $dbpass){
if($dbactive == 1){
//sets session info
$_SESSION['userid'] = $dbid;
$_SESSION['username'] = $dbuser;
echo "you have been logged in as <b>$dbuser</b>. <a href='./member.php'>Click here</a> to go to member page";
}
else
echo "You must activate your account to login. $form";
}
else
echo "You didnt enter the right pass. $form";
}
else
echo "The username you entered was not found. $form";
mysql_close();//closes connection
}
else
echo "You must enter your password. $form";
}
else
echo "You must enter your username. $form";
}
else
echo $form;
?>
</body>
</html>
2 个解决方案
解决方案1
2 已采纳 2015-03-27 11:13:28
You dont need to use 8080 simply use localhost because that port number is not related to mysql but related to webserver. 您不需要使用8080即可简单地使用localhost因为该端口号与mysql不相关，但与Web服务器相关。 Inorder to address the webserver only you need to use it like localhost:8080/project-name/ 为了仅访问网络服务器，您需要使用它，例如localhost:8080/project-name/
And dont use mysql_* methods. 并且不要使用mysql_*方法。 will get disappointed in future. 将来会失望的。 Use mysqli 使用mysqli
$con = new mysqli("localhost","root","","membersystem") or die('Connection failed');
$result = $con->query("Your query here");
or else you can use the same in procedural method with mysqli_* functions. 否则，您可以在mysqli_*函数的过程方法中使用相同的方法。 But i prefer to go along with object oriented php. 但是我更喜欢与面向对象的php一起使用。
Refer the documentation. 请参阅文档。 http://php.net/manual/en/book.mysqli.php http://php.net/manual/en/book.mysqli.php
解决方案2
1 2015-03-27 11:11:34
Make connection like 建立像
$conn=mysqli_connect("localhost","root","","membersystem");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
and w3schools link is http://www.w3schools.com/php/func_mysqli_select_db.asp 和w3schools链接是http://www.w3schools.com/php/func_mysqli_select_db.asp
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