[英]c++ Polymorphism : segfault and reference strange behaviour with arrays
Here is a MWE that, when compiled with g++ -std=c++11
, produces a segmentation fault: 这是一个MWE ,当使用
g++ -std=c++11
编译时,会产生分段错误:
#include <iostream>
#include <random>
class Rand{
public:
Rand(double const& min_inclusive, double const& max_exclusive):
mt_(std::random_device()()),
dist_(min_inclusive,max_exclusive){}
~Rand(){}
double get() { return dist_(mt_); }
private:
std::mt19937_64 mt_;
std::uniform_real_distribution<double> dist_;
};
class Base {
public:
Base():rnd(0.0,1.0){ std::cout<<"Base created "<<&rnd<<" "<<rnd.get()<<std::endl; }
virtual ~Base(){};
Rand rnd;
};
class Child: public Base{
public:
Child():var(1.0){ std::cout<<"Child created"<<std::endl; }
double var;
};
class Other {
public:
Other(Base* b):b(b){ std::cout<<"Other created "<<&(b[0].rnd)<<" and "<<&(b[1].rnd)<<"--->"<<b[0].rnd.get()<<" "<<b[1].rnd.get()<<std::endl; }
Base* b;
};
int main(){
unsigned int N(2);
std::cout<<"#############"<<std::endl;
Base* b(new Base[N]);
Other o1(b);
std::cout<<"#############"<<std::endl;
Child* c(new Child[N]);
Other o2(c);
std::cout<<"#############"<<std::endl;
delete[] b;
delete[] c;
}
The typical output is : 典型的输出是:
#############
Base created 0x239c020 0.226514
Base created 0x239ca00 0.902337
Other created 0x239c020 and 0x239ca00--->0.864321 0.302185
#############
Base created 0x239d3f0 0.573563
Child created
Base created 0x239ddd8 0.422187
Child created
Other created 0x239d3f0 and 0x239ddd0--->0.909183 4.94066e-324
#############
In the first part where a Base
class is given to Other
the references are coherent and the code runs properly. 在将
Base
类提供给Other
的第一部分中,引用是一致的,并且代码可以正常运行。
But when a Child
class is given to Other
, the first reference is identical but the second is slightly different. 但是,当将
Child
类提供给Other
,第一个引用是相同的,但第二个引用则略有不同。 The direct consequence of that is that the b[1].rdn.get()
is always (very close) '0'. 这样做的直接结果是
b[1].rdn.get()
始终(非常接近)为'0'。 The other indirect consequence is that the code ends with a SegFault... 另一个间接后果是代码以SegFault结尾。
Moreover, when Child::var
is absent, the program works fine, all references are coherent and there is no SegFault. 此外,如果不存在
Child::var
,则程序可以正常运行,所有引用均一致,并且没有SegFault。
What am I doing wrong ? 我究竟做错了什么 ? Is it impossible to create
Other
with a child of Base
? 用
Base
的子Base
创建Other
是不可能的吗? If so, it looks like the polymorphism is ruined... 如果是这样,看起来多态性就毁了……
According to a nice answer : 根据一个不错的答案:
#include <iostream>
#include <random>
#include <vector>
#include <memory>
class Rand{
public:
Rand(double const& min_inclusive, double const& max_exclusive):
mt_(std::random_device()()),
dist_(min_inclusive,max_exclusive){}
~Rand(){}
double get() { return dist_(mt_); }
private:
std::mt19937_64 mt_;
std::uniform_real_distribution<double> dist_;
};
class Base {
public:
Base():rnd(0.0,1.0){ std::cout<<"Base created "<<&rnd<<" "<<rnd.get()<<std::endl; }
virtual ~Base(){};
Rand rnd;
};
class Child: public Base{
public:
Child():var(0.0){ std::cout<<"Child created"<<std::endl; }
double var;
};
template<typename Type>
class Other {
public:
Other(unsigned int N):b_(N){
std::cout<<"Other created "<<std::endl;
for(unsigned int i(0);i<b_.size();i++){
b_[i] = std::make_shared<Type>();
}
}
std::vector<std::shared_ptr<Base> > b_;
};
int main(){
unsigned int N(2);
std::cout<<"#############"<<std::endl;
Other<Base> o1(N);
std::cout<<"#############"<<std::endl;
Other<Child> o2(N);
std::cout<<"#############"<<std::endl;
}
If you have an array of Child
you can't treat it as an array of Base
. 如果您有一个
Child
数组,则不能将其视为Base
数组。 This means that when for example you call b[1].rnd.get()
, you invoke undefined behavior. 这意味着例如当您调用
b[1].rnd.get()
,您将调用未定义的行为。
Why is that? 这是为什么? When you have a
Child* c
and you convert it to Base*
, the result of conversion is a pointer to a Base
subobject of Child
. 当您拥有
Child* c
并将其转换为Base*
,转换的结果是一个指向Child
的Base
子对象的指针。 So (Base*)c + 1
will point to the next byte after that subobject, which in your case is the first byte of var
. 因此,
(Base*)c + 1
将指向该子对象之后的下一个字节,在您的情况下,它是var
的第一个字节。
When Child
doesn't have data members, (Base*)c + 1
points to the next object, so everything works. 当
Child
没有数据成员时, (Base*)c + 1
指向下一个对象,因此一切正常。
In order to achieve polymorphic behavior you should create an array of pointers to Base
: 为了实现多态行为,您应该创建一个指向
Base
的指针数组:
Base** b{new Base*[N]};
Initialize each array element with whatever descendant of Base
and enjoy polymorphism. 使用
Base
任何后代初始化每个数组元素,并享受多态性。
Edit: as it was reasonably pointed out by vsoftco in the comments, it's better not to use raw pointers and arrays: 编辑:正如vsoftco在评论中合理指出的那样,最好不要使用原始指针和数组:
std::vector<std::shared_ptr<Base>> b {...}
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