如何使用 SWIG 在 C++ 中调用 python 函数？

Question

I have a the following C++

class myfun{
public:
    virtual double eval(arma::vec& x){};
};

double op(myfun* f, arma::vec& x){
    return f->eval(x);
}

where arma::vec is an armadillo c++ vector for which I am using armanpy.i to translate a numpy array as an arma::vec object and vice versa.

After enabling the swig directors, and creating a SWIG interface for the above C++ code, I create a python class which redefine's the eval virtual method:

class f(mymodule.myfun):
    def __init__(self):
        super(f,self).__init__()
    def eval(self,x):
        print x
        return 3.14

In python, I first create an instance of f, which inherits myfun:

b = f()

Then, I pass this to op :

mymodule.op(b,array([3.,4.]))

which outputs

<Swig Object of type 'arma::vec *' at 0x10e6dcc30>
3.14

Python is not interpreting arma::vec * as a numpy array, which I thought it was doing in the armanpy.i file. Any ideas? I am not married to arma::vec and I could replace arma::vec with a numpy vector.

Thanks!

Answer 1

在您的情况下，请查看提供 armadillo SWIG 文件的armanpy 。

Answer 2

You can accomplish this using this repository at Github which makes use of armanpy and armadillo 8.500.1

https://github.com/Wolframm74/armadillo_armanpy/blob/master/README.md

Start with compiling the code by following the steps and then building upon the examples. It has examples with how to translate python's numpy arrays into armadillo arrays via SWIG.