无法在Hibernate中将java.lang.Integer字段…User.id设置为java.lang.Integer异常

Question

I am building RESTful service with hibernate Jersey and Spring on java and realized that relationships between my entities should be without including instance of classes, just identifiers (foreign keys). But I have exceptions when try to query entities. I have following entities:

@Entity
@javax.persistence.Table(name = "manager_user")
public class ManagerUser extends User {

    @ManyToOne(targetEntity = ShopAdminUser.class)
    private Integer shopAdminUserId;
//...
}


@Entity
@javax.persistence.Table(name = "shop_admin_user")
public class ShopAdminUser extends User {

    @Lob
    private String contactData;

    public String getContactData() {
        return contactData;
    }

    public void setContactData(String contactData) {
        this.contactData = contactData;
    }
}


@Entity
@Inheritance(strategy= InheritanceType.TABLE_PER_CLASS)
public abstract class User {

    @Id
    @GeneratedValue(strategy = GenerationType.TABLE)
    private Integer id;

    private String firstName;
    private String lastName;

    @Temporal(TemporalType.DATE)
    private Date dob;

    @Enumerated(EnumType.STRING)
    private Gender gender;

    @Column(unique = true, nullable = false)
    private String email;
    @Column(nullable = false)
    private String password;

    @Lob
    private String personalData;

    @OneToOne(targetEntity = Photo.class)
    private Integer photoId;

//...getters and setters
}

And I am getting exception in the next method:

@Transactional(readOnly = true)
public List<ManagerUser> getByShopAdminUserID(Integer id) {
    Session session = sessionFactory.getCurrentSession();
    List managerUsers = session.createQuery(
            "from ManagerUser m where m.shopAdminUserId = :shopAdminUserId")
            .setParameter("shopAdminUserId", id).list();
    return managerUsers;
}

Stack trace:

Mar 28, 2015 4:10:56 PM com.sun.jersey.spi.container.ContainerResponse mapMappableContainerException
SEVERE: The RuntimeException could not be mapped to a response, re-throwing to the HTTP container
org.hibernate.PropertyAccessException: could not get a field value by reflection getter of com.foodservice.businesslogic.user.ShopAdminUser.id
    at org.hibernate.property.DirectPropertyAccessor$DirectGetter.get(DirectPropertyAccessor.java:60)
    at org.hibernate.tuple.entity.AbstractEntityTuplizer.getIdentifier(AbstractEntityTuplizer.java:346)
    at org.hibernate.persister.entity.AbstractEntityPersister.getIdentifier(AbstractEntityPersister.java:4746)
    at org.hibernate.persister.entity.AbstractEntityPersister.isTransient(AbstractEntityPersister.java:4465)
    at org.hibernate.engine.internal.ForeignKeys.isTransient(ForeignKeys.java:243)
    at org.hibernate.engine.internal.ForeignKeys.getEntityIdentifierIfNotUnsaved(ForeignKeys.java:293)
    at org.hibernate.type.EntityType.getIdentifier(EntityType.java:537)
    at org.hibernate.type.ManyToOneType.nullSafeSet(ManyToOneType.java:174)
    at org.hibernate.param.NamedParameterSpecification.bind(NamedParameterSpecification.java:67)
    at org.hibernate.loader.hql.QueryLoader.bindParameterValues(QueryLoader.java:616)
    at org.hibernate.loader.Loader.prepareQueryStatement(Loader.java:1901)
    at org.hibernate.loader.Loader.executeQueryStatement(Loader.java:1862)
    at org.hibernate.loader.Loader.executeQueryStatement(Loader.java:1839)
    at org.hibernate.loader.Loader.doQuery(Loader.java:910)
    at org.hibernate.loader.Loader.doQueryAndInitializeNonLazyCollections(Loader.java:355)
    at org.hibernate.loader.Loader.doList(Loader.java:2554)
    at org.hibernate.loader.Loader.doList(Loader.java:2540)
    at org.hibernate.loader.Loader.listIgnoreQueryCache(Loader.java:2370)
    at org.hibernate.loader.Loader.list(Loader.java:2365)
    at org.hibernate.loader.hql.QueryLoader.list(QueryLoader.java:497)
    at org.hibernate.hql.internal.ast.QueryTranslatorImpl.list(QueryTranslatorImpl.java:387)
    at org.hibernate.engine.query.spi.HQLQueryPlan.performList(HQLQueryPlan.java:236)
    at org.hibernate.internal.SessionImpl.list(SessionImpl.java:1264)
    at org.hibernate.internal.QueryImpl.list(QueryImpl.java:103)
    at com.foodservice.dao.ManagerUserDAO.getByShopAdminUserID(ManagerUserDAO.java:50)
    at com.foodservice.dao.ManagerUserDAO$$FastClassBySpringCGLIB$$7447621a.invoke(<generated>)
...
Caused by: java.lang.IllegalArgumentException: Can not set java.lang.Integer field com.foodservice.businesslogic.user.User.id to java.lang.Integer
    at sun.reflect.UnsafeFieldAccessorImpl.throwSetIllegalArgumentException(UnsafeFieldAccessorImpl.java:167)
    at sun.reflect.UnsafeFieldAccessorImpl.throwSetIllegalArgumentException(UnsafeFieldAccessorImpl.java:171)
    at sun.reflect.UnsafeFieldAccessorImpl.ensureObj(UnsafeFieldAccessorImpl.java:58)
    at sun.reflect.UnsafeObjectFieldAccessorImpl.get(UnsafeObjectFieldAccessorImpl.java:36)
    at java.lang.reflect.Field.get(Field.java:393)
    at org.hibernate.property.DirectPropertyAccessor$DirectGetter.get(DirectPropertyAccessor.java:57)
    ... 120 more

EDIT

My SQL provided by Hibernate

Hibernate: 
    select
        manageruse0_.id as id1_0_,
        manageruse0_.dob as dob2_0_,
        manageruse0_.email as email3_0_,
        manageruse0_.firstName as firstNam4_0_,
        manageruse0_.gender as gender5_0_,
        manageruse0_.lastName as lastName6_0_,
        manageruse0_.password as password7_0_,
        manageruse0_.personalData as personal8_0_,
        manageruse0_.photoId_id as photoId11_0_,
        manageruse0_.systemStatus as systemSt9_0_,
        manageruse0_.userType as userTyp10_0_,
        manageruse0_.shopAdminUserId_id as shopAdmi2_6_,
        manageruse0_.state as state1_6_ 
    from
        manager_user manageruse0_ 
    where
        manageruse0_.shopAdminUserId_id=?
Hibernate: 

select
    shopadminu0_.id as id1_0_0_,
    shopadminu0_.dob as dob2_0_0_,
    shopadminu0_.email as email3_0_0_,
    shopadminu0_.firstName as firstNam4_0_0_,
    shopadminu0_.gender as gender5_0_0_,
    shopadminu0_.lastName as lastName6_0_0_,
    shopadminu0_.password as password7_0_0_,
    shopadminu0_.personalData as personal8_0_0_,
    shopadminu0_.photoId_id as photoId11_0_0_,
    shopadminu0_.systemStatus as systemSt9_0_0_,
    shopadminu0_.userType as userTyp10_0_0_,
    shopadminu0_.contactData as contactD1_16_0_,
    photo1_.id as id1_9_1_,
    photo1_.image as image2_9_1_,
    photo1_.name as name3_9_1_ 
from
    shop_admin_user shopadminu0_ 
left outer join
    photo photo1_ 
        on shopadminu0_.photoId_id=photo1_.id 
where
    shopadminu0_.id=?

What I am doing wrong? Help me)

Answer 1

i got a seem question.now i solve it.it's simple. your code-->

@ManyToOne(targetEntity = ShopAdminUser.class)
private Integer shopAdminUserId;

should be

@ManyToOne(targetEntity = ShopAdminUser.class)
@JoinColumn(name="shopAdminUserId" references...=""(i forget how to spell))
private ShopAdminUser shopAdminUser;

and so does this:

@OneToOne(targetEntity = Photo.class)
private Integer photoId;

should be

 @OneToOne(targetEntity = Photo.class)
@JoinColumn(name="photoId" references...=""(i forget how to spell))
private Photo photo;

because hibernate will auto converse the class to int or something else

Answer 2

try to make no argument constructer in class (ShopAdminUser and ManagerUser). Hibernate uses it to instatiate entity.