Preg匹配字符串以使用正则表达式查找->的所有匹配项

Question

I'm having a small technical difficulty with a regular expression, I'm trying to look at a string, let's say we have this string:

$string = "error->400";

And another string:

$string = "error->debug->warning";

As an example, I'm basically trying to do a preg_match() that returns true on any instances of -> within it.

This is my attempt but I don't understand why it doesn't work:

preg_match("/^[->]*$/", $string);

Is there a general rule for custom characters that i'm generally missing?

Thanks.

Answer 1

Right now, ^[->]*$ matches any number of "-" or ">" characters, from the beginning to end. You must use a group, not a character class, and anchors are not necessary. Use this to check if "->" is present in the $string :

 preg_match("/(->)/", $string);

Have a look at the example .