用bash中的数组元素算术

Question

I'm using bash and trying to add all elements of an array that was created from a file.

while read line; do
    array=($line);
    sum=0
    length=${#array[@]}
    for i in ${array[@]:0:$length}; do
       sum=$[$sum+${array[i]}]   #<--- this doesn't work?
    done
    echo $sum
done < $1

edit: I should have been clearer why i want to use array splitting in for loop

The input may be ------> david 34 28 9 12

And I want to print ---> david 83

So I would like to loop through all elements accept the first one. so i would use:

length=$[${#array[@]} - 1]
for i in${array[@]:1:$length}

because of this i can't use:

for i in "${array[@]}"

Answer 1

Try using expr to add two expression something like:

sum=$(expr "$sum" + "${arr[i]}")

Or

sum=$((sum + arr[i]))


echo "11 13" >test.txt 
echo "12" >>test.txt

while read -a line; do ##read it as array
    sum=0
    for ((i=1; i < ${#line}; i++)); do ##for every number in line
       sum=$(expr "$sum" + "${line[i]}") ## add it to sum
    done
    echo $line[0] $sum ##print sum
done < test.txt
Output
36

After OP's edit:

echo "ABC 11 13" >test.txt echo "DEF 12" >>test.txt

while read -a line; do ##read it as array
sum=0
for ((i=1; i < $((${#line[@]})); i++)); do ##for every number in line
   sum=$(expr "$sum" + "${line[i]}") ## add it to sum
   if [[ $i -eq $((${#line[@]}-1)) ]]
   then
       echo "${line[0]} $sum" ##print sum
       sum=0
   fi
done
done < test.txt
Output:
ABC 24
DEF 12

Answer 2

If you want to sum the numbers in each lines of the file using a loop in bash you could do

#!/bin/bash
while read line; do
    array=($line);
    sum=0
    length=${#array[@]}
    for i in ${array[@]:0:$length}; do
       sum=$[$sum+$i]
    done
    echo $sum
done < "$1"

The difference with your code is that i is the element in the array, not the index.

However, possessing files in bash is rather slow. You would be probably better off to do the task in awk, like this for example:

awk '{s=0;for(i=1;i<=NF;i++) s+=$i;print s}' file