使用python列出所有USB大容量存储磁盘

Question

I have few USB disks inserted in my system. I would like to list all of them like:-

/dev/sdb
/dev/sdc
.... ans so on..

Please remember that I don't want to list partitions in it like /dev/sdb1 . I am looking for solution under Linux. Tried cat /proc/partitions .

major minor  #blocks  name

   8        0  488386584 sda
   8        1   52428800 sda1
   8        2   52428711 sda2
   8        3          1 sda3
   8        5   52428800 sda5
   8        6   15728516 sda6
   8        7  157683712 sda7
   8        8  157682688 sda8
  11        0    1074400 sr0
  11        1      47602 sr1
   8       32    3778852 sdc
   8       33          1 sdc1
   8       37    3773440 sdc5

But it list all the disks and unable to figure which one is USB storage disks. I am looking for a solution which does not require an additional package installation.

Answer 1

在/dev列出正确的路径：

ls -l /dev/disk/by-path/*-usb-* | fgrep -v part

Answer 2

You can convert Klaus D.'s suggestion into Python code like this:

#!/usr/bin/env python

import os

basedir = '/dev/disk/by-path/'

print 'All USB disks'

for d in os.listdir(basedir):
    #Only show usb disks and not partitions
    if 'usb' in d and 'part' not in d:
        path = os.path.join(basedir, d)
        link = os.readlink(path)
        print '/dev/' + os.path.basename(link)

path contains info in this format:
/dev/disk/by-path/pci-0000:00:1d.7-usb-0:5:1.0-scsi-0:0:0:0
which is a symbolic link, so we can get the pseudo-scsi device name using os.readlink() .
But that returns info in this format:
../../sdc
so we use os.path.basename() to clean it up.

Instead of using
'/dev/' + os.path.basename(link)
you can produce a string in the '/dev/sdc' format by using
os.path.normpath(os.path.join(os.path.dirname(path), link))
but I think you'll agree that the former technique is simpler. :)