[英]Why am I getting this error “Error: Query was empty”
I am trying to update my SQL database using a form through php, but i keep getting the error "Error: Query was empty". 我正在尝试通过php使用表单更新SQL数据库,但我不断收到错误“错误:查询为空”。
<?php
$sql = "";
$con = mysql_connect("*******","*******");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("*******", $con);
mysql_query($sql, $con);
if (isset($_POST['STUDENT_FNAME'], $_POST['STUDENT_SNAME'],
$_POST['STUDENTNO'] ))
{
$sql="UPDATE STUDENT SET STUDENT_FNAME=('$_POST[STUDENT_FNAME]'),
STUDENT_SNAME=('$_POST[STUDENT_SNAME]')
WHERE STUDENTNO=
('$_POST[STUDENTNO]')";
}
if (!mysql_query($sql,$con))
{
die('Error: ' . mysql_error());
}
echo "1 record updated";
mysql_close($con);
?>
It also won't update my table and I don't know what I've done wrong. 它也不会更新我的表,我也不知道我做错了什么。 All help will be much appreciated.
所有帮助将不胜感激。 I am new to this as you can probably tell!
您可能会告诉我,我是新手!
Remove mysql_query($sql, $con)
query execution after db selection because $sql
is empty, 选择数据库后删除
mysql_query($sql, $con)
查询执行,因为$sql
为空,
Also put your update sql execution in IF conditions , because if its not true than again $sql will be empty and you will get same error again,... 还要将更新sql执行置于IF条件下 ,因为如果它不正确,那么$ sql将再次为空,并且您将再次得到相同的错误,...
<?php
$sql = "";
$con = mysql_connect("*******","*******");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("*******", $con);
// mysql_query($sql, $con); // <-- remove this
if (isset($_POST['STUDENT_FNAME'], $_POST['STUDENT_SNAME'],
$_POST['STUDENTNO'] ))
{
$sql="UPDATE STUDENT SET STUDENT_FNAME=('$_POST[STUDENT_FNAME]'),
STUDENT_SNAME=('$_POST[STUDENT_SNAME]')
WHERE STUDENTNO=
('$_POST[STUDENTNO]')";
if (!mysql_query($sql,$con))
{
die('Error: ' . mysql_error());
}
echo "1 record updated";
}
mysql_close($con);
?>
There is an error in your code first you are calling mysql_query($sql, $con); 首先,您在调用mysql_query($ sql,$ con);的代码中出现错误。 without any query in your $sql variable your $sql is blank ""
在$ sql变量中没有任何查询的情况下,$ sql为空“”
<?php
$sql = "";
$con = mysql_connect("*******","*******");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("*******", $con);
if (isset($_POST['STUDENT_FNAME'], $_POST['STUDENT_SNAME'],
$_POST['STUDENTNO'] ))
{
$sql="UPDATE STUDENT SET STUDENT_FNAME=('$_POST[STUDENT_FNAME]'),
STUDENT_SNAME=('$_POST[STUDENT_SNAME]')
WHERE STUDENTNO=
('$_POST[STUDENTNO]')";
}
if (!mysql_query($sql,$con))
{
die('Error: ' . mysql_error());
}
echo "1 record updated";
mysql_close($con);
?>
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