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PowerShell查询的SCCM LastLogonTimestamp格式

[英]SCCM LastLogonTimestamp format queried by PowerShell

I would like to know how it is possible to convert the LastLogonTimestamp found in the SCCM database to a readable format. 我想知道如何将SCCM数据库中找到的LastLogonTimestamp转换为可读格式。 The code I have now is the following: 我现在的代码如下:

$SCCMServer = 'SERVERSCCM'
$SCCMModule = 'C:\Program Files (x86)\Microsoft Configuration Manager\bin\ConfigurationManager.psd1'
$SamAccountName = 'test'

Function Get-SCCMSite { 
    Param (
        [Parameter(Mandatory=$true)]
        [String]$ComputerName
    )
    Process {
        Get-WmiObject -ComputerName $ComputerName -Namespace 'root\SMS' -Class 'SMS_ProviderLocation' | 
            ForEach-Object{ 
                if ($_.ProviderForLocalSite -eq $true) {$SiteCode=$_.sitecode} 
        } 
        if ($SiteCode -eq '') {
            throw ('Sitecode of ConfigMgr Site at ' + $ComputerName + ' could not be determined.') 
        }
        else { 
            Return $SiteCode 
        } 
    }
}

Import-Module $SCCMModule
$SCCMSite = Get-SCCMSite -ComputerName $SCCMServer
Set-Location "$SCCMSite`:"
$SCCMNameSpace="root\SMS\site_$SCCMSite"

Get-WmiObject -namespace $SCCMNameSpace -computer $SCCMServer -query "select * from sms_r_system where LastLogonUserName='$SamAccountName'" | select *

The output of LastLogonTimestamp looks like this: LastLogonTimestamp的输出如下所示:

LastLogonTimestamp            : 20150330132039.000000+***

On the web I found that this format could be converted to a readable format like this: 在网络上,我发现这种格式可以转换为可读格式,如下所示:

[datetime]::FromFileTime(20150330132039.000000+***).ToString('d MMMM yyyy')

But it's not really working as it outputs errors. 但它并没有真正起作用,因为它输出错误。 When I remove the last part behind the . 当我删除后面的最后一部分. it gives me a date in 1601, which is definitely incorrect. 它给我一个1601年的日期,这绝对不正确。

I don't think the FromFileTime method is the correct one for this situation. 我不认为FromFileTime方法对于这种情况是正确的。

You can use the ParseExact method with a bit of manipulation of the original value: 您可以使用ParseExact方法对原始值进行一些操作:

> $lastlogonstamp = "20150330132039.000000+***"
> $dt = [datetime]::parseexact($lastlogonstamp.split('.')[0],"yyyyMMddHHmmss",[System.Globalization.CultureInfo]::InvariantCulture)
> $dt

30 March 2015 13:20:39

> $dt.ToString('d MMMM yyyy')
30 March 2015

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