如何从Servlet发送json数据响应到特定的Url（Server）？

Question

I have the following code which is with json format data as input variables in the html form. 我有以下代码，其中json格式的数据作为html形式的输入变量。

out.write("<html><body onload=\"document.forms[0].submit()\">\n");
      out.write("<form  enctype='application/json' method=\"POST\" action=\"" + resourcePath + "\">\n");
      out.write("<input name='sessionId' value=\"" + sessionId + "\"/>\n");
      out.write("<input name='sessionValid' value=\"" + true + "\"/>\n");
      out.write("</form>\n</body>\n</html>\n");

I have googled about this and i got the above format but it is not working, still it is taking as a normal string while reading after form has been submitted. 我已经对此进行了谷歌搜索，但是得到了以上格式，但它无法正常工作，但在提交表单后仍在读取时仍将其作为普通字符串。 I have seen same type of questions in stack overflow also but they are directing me to use jquery which i do not want to use. 我也曾在堆栈溢出中看到过相同类型的问题，但它们指示我使用我不想使用的jquery。

What might be the wrong in the above code? 上面的代码可能是什么错误？

Answer 1

Its very hard to tell with the current example given, it would seem there is more of a syntax error or possibly some issue with the browser or submitting to the server side. 给出的当前示例很难说清，似乎有更多的语法错误，或者浏览器或提交到服务器端可能出现问题。

Here is a bare basic example that can be tested if you have PHP... just create a test.php file or something and use the following code. 这是一个简单的基本示例，如果您有PHP，可以进行测试...只需创建一个test.php文件或其他内容，然后使用以下代码即可。 If this works, then it would be the variables used or the way they are being created/echoed in place. 如果可行，则可能是所使用的变量或就地创建/回显它们的方式。

<?php
    if (isset($_REQUEST['sessionId'])) {
        echo "<pre>".print_r($_REQUEST, true)."</pre>";
        exit;
    }
?>
<form enctype='application/json' method="POST">
    <input name='sessionId' value="has7ft8f7w56ef78wte"/>
    <input name='sessionValid' value="true"/>
    <button type='submit'>Submit</button>
</form>

If you can provide some more information, i'll do what i can to help out in this case.. Some times when things dont work.. best to go back to basics for testing then see where it breaks. 如果您可以提供更多的信息，在这种情况下，我会尽力提供帮助。.有时候事情不起作用..最好回到基础进行测试，然后看看有什么坏处。

EDIT 编辑

<form enctype='application/json' method="POST" action="myurl_or_where_ever">
    <input name='sessionId' value="has7ft8f7w56ef78wte"/>
    <input name='sessionValid' value="true"/>
    <button type='submit'>Submit</button>
</form>

By testing with something as simple as this, you're making sure the basic concept works.. If this works, then change the action="" first.. if that works, then change the sessionId/Valid.. The button is to simply rule out the onload event.. This is part of debugging and will save you alot of time in the future. 通过这样简单的测试，您可以确保基本概念有效。如果有效，则首先更改action =“”。如果有效，则更改sessionId / Valid。按钮是只需排除onload事件即可。这是调试的一部分，将来可以节省很多时间。

Replace "myurl_or_where_ever" with the expected value of "resourcePath" 将“ myurl_or_where_ever”替换为“ resourcePath”的期望值

如何从Servlet发送json数据响应到特定的Url（Server）？

问题描述

1 个解决方案

解决方案1
0 2015-04-06 07:19:41

如何从Servlet发送json数据响应到特定的Url（Server）？

问题描述

1 个解决方案

解决方案1 0 2015-04-06 07:19:41

解决方案1
0 2015-04-06 07:19:41