在C中打印ASCII码值及其等效字符

Question

How could I print char for given ASCII code value?..

I saw this question , my problem is similar, just contrary

Below is my program, but it doesn't work.

int main (){
int code;     // code that user enters
char ch;      //"codes" related ASCII charcter

printf("Enter a ASCII code value: \n");
scanf("%d", &code);
ch=code;

printf(" %c is cherechter that have %d ASCII code\n", &ch ,&code);

system("PAUSE");
return 0;}  

Answer 1

In your code, you have to change your printf statement

printf(" %c is cherechter that have %d ASCII code\n", &ch ,&code);

to

printf(" %c is cherechter that have %d ASCII code\n", ch ,code);

because, to print the values , you don't need to supply the address of the variables. The variable name is enough.

Answer 2

Change your code to:

int main (){
char code;   //change from int to char  
char ch;      

printf("Enter a ASCII code value: \n");
scanf("%c", &code);//ASCII is a character not integer
ch=code;

printf(" %c is cherechter that have %x and %d ASCII code\n", ch ,code,code);//don't print the address access the value

system("PAUSE");
return 0;}