人的模糊匹配列表

Question

I am trying to see if a movie is the same between two pages, and to do so I would like to compare the Actors as one of the criteria. However, actors are often listed differently on different pages. For example:

• On this page, https://play.google.com/store/movies/details?id=cSdcb2KOH74 , the actors are listed as "Mikhail Galustyan, Danny Trejo, Guillermo Díaz, Oleg Taktarov, Kym Whitley, Christopher Robin Miller, Robert Bear, Vladimir Yaglych, Josh McLerran"

• One this page, http://www.imdb.com/title/tt2167970/ , the actors as "Ivan Stebunov, Ingrid Olerinskaya, Vladimir Yaglych"

Previously, I was doing a very rough match on:

if actors_from_site_1[0] == actors_from_site_2[0]

But, as you can see from the above case, this isn't a good technique. What would be a better technique to see if the actors from one film match the others?

Answer 1

You could check the length of a set intersection of the two sets of actors.

if len(set(actors_from_site_1).intersection(set(actors_from_site_2))):

or you could do something like:

if any(actor in actors_from_site_1 for actor in actors_from_site_2):

Answer 2

If all the lists are comma separated actor names, split them on the commas, lowercase the names, and get the intersection:

actors_from_site_1 = set(actors_from_site_1.lower().split(','))
actors_from_site_2 = set(actors_from_site_2.lower().split(','))

common_actors = actors_from_site_1 & actors_from_site_2

Answer 3

Try:

similaractors = []
for actor in actors_from_site_1:
    if actor in actors_from_site_2:
        similaractors.append(actor)

Then, you have similaractors as a list of all the actors they share. Call len(similaractors) to get the number of similar actors, and then you can print(similaractors) and do everything else you might do with a list.