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用HTML标签+ \\ n替换关闭的HTML标签

[英]Replacing closing HTML tags with HTML tag + \n

I'm trying to replace generally closing html tags with the closing tag + a line break, i found similar posts here on SO, none really helped me to accomplish what I'm looking for. 我试图用结束标记+换行符代替通常结束的html标记,所以我在这里找到了类似的帖子,没有一个真正帮助我完成想要的事情。

</li> would be </li>\\n </li>应该是</li>\\n

<img some property /> would be <img some property />\\n <img some property />将是<img some property />\\n

I managed to do that in php with the following funtion, which works well: 我设法通过以下功能在php中做到了,效果很好:

 public static function addLBinHTML($htmlcode){

     $pattern= array('~(</.*?>)~','(/>)');
     $replace= array('${1} Hallo \n  ','/>\n  ');

     return preg_replace($pattern, $replace, $htmlcode);
}

I'm trying to do the same in JavaScript / jQuery and I'm failing on getting the variable(in php regex ${1} ). 我试图在JavaScript / jQuery中执行相同的操作,但未能获取变量(在php regex ${1} )。

I tried with .split .join and with .replace, and I think .replace is the right way to go. 我尝试了.split .join和.replace,我认为.replace是正确的方法。

Here is what I got (my last and hopefully closest attempt) 这就是我得到的(我最后一次也是最接近的尝试)

function setLinebreaks(taID){

   var strContent = $('#'+taID).val();
   var regex = new RegExp("</.*?>", "gi");

    strContent.replace(regex, "${1} \n   ")
              .replace(/\/>/g,'/> \n    ');

   console.log(strContent);
   $('#'+taID).val(strContent);
}

Thanks in advance for your help 在此先感谢您的帮助

You have to capture the regular expression with brackets, assign the replaced string and replace ${1} by $1 : 你必须捕捉与括号中的正则表达式, 指定替换字符串和替换${1}$1

var regex = new RegExp("(</.*?>)", "gi");

strContent = strContent.replace(regex, "$1 \n   ")
                       .replace(/\/>/g,'/> \n    ');

Or you can simply put the replace methods into the val function. 或者,您可以简单地将replace方法放入val函数中。

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