[英]Issue with Rails link_to if method
In my Ruby on Rails application I have method that looks like this: 在我的Ruby on Rails应用程序中,我具有如下所示的方法:
def survey_pack_signed_off(sp, type)
signed_off = Util::Boolean.humanize(sp.survey_pack_sign_off.present?)#returns Yes if true and No if false
return signed_off if type == :csv
if sp.survey_pack_sign_off.present?
link_to signed_off, admin_survey_pack_sign_off_path(sp.survey_pack_sign_off)
else
signed_off
end
end
I was trying to refactor it and use Rails link_to_if method: 我试图对其进行重构,并使用Rails link_to_if方法:
def survey_pack_signed_off(sp, type)
signed_off = Util::Boolean.humanize(sp.survey_pack_sign_off.present?)#returns Yes if true and No if false
return signed_off if type == :csv
link_to_if (type == :html && sp.survey_pack_sign_off.present?), signed_off, admin_survey_pack_sign_off_path(sp.survey_pack_sign_off)
end
But this link_to_if causes following error: 但是此link_to_if导致以下错误:
ActionController::UrlGenerationError: No route matches {:action=>"show", :controller=>"admin/survey_pack_sign_offs", :format=>nil, :id=>nil} missing required keys: [:id]
Why this code not works? 为什么此代码不起作用?
Try to set id
explicitly: 尝试显式设置id
:
admin_survey_pack_sign_off_path(id: sp.survey_pack_sign_off)
If I correctly understood your code and survey_pack_sign_off
contains some id of the page 如果我正确理解您的代码,并且survey_pack_sign_off
包含页面的某些ID
The solution is: 解决方案是:
spso = sp.survey_pack_sign_off
link_to_if spso, signed_off, spso ? admin_survey_pack_sign_off_path(spso) : nil
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