使用Shell脚本对文件进行排序，然后删除旧文件

Question

I have a folder with some normal files. I want to sort them by their modified date, keeps the latest 20 entries, and from what's left, erases anything older than 20 days.

Here is my code to delete files those are > 20 days.

#!/bin/bash
cleanup="../some path/"

find $cleanup/*gz -mtime +20 -exec rm {} \;

However, I don't know how to keep the last modified 20 files, then doing the delete. How to fix it please?

Answer 1

You can filter 20 filenames out with

awk 'NR > 20' 

Full command:

find ...... | awk 'NR > 20' | xargs -r  rm

For example

seq 30 | xargs -i echo 'file{}' | awk 'NR > 20' | xargs  -r rm