Javascript：修剪数组中字符串的长度

Question

I would like to ask if it is possible to trim the length of multiple strings in an array in javascript. The length of each string of my array is different, however I would like to trim the last 2 digit (meaning trimming "-2") for each of them.

var array = ["517577144-2","503222534-2","100003527692828-2","654703438-2","4205501-2"]

Cheers, Karen

Answer 1

map function:

array = array.map(function(d){return d.substr(0,d.length-2)});

or you can use slice method inside:

array = array.map(function(d){return d.slice(0,-2)});

Answer 2

另一个选择是您可以将map与slice函数一起使用：

array = array.map(function(str){return str.slice(0,str.length-2)});

Answer 3

Look at the 'map' function. This should do it for you: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/map

Answer 4

You can try like this:

var x;
for(x = 0; x < 10; x++)
{
    array[x] = array[x].replace('-2', '');
}

JSFIDDLE DEMO

Answer 5

This will remove the last character -2 in the array.

   array = array.map(function(item) {
      return item.replace('-2', '');
    })

If you want to remove any character which is at the last not specifically -2 then

 array = array.map(function(item) {
      return item.substr(0, item.length-2);
    })

Answer 6

Multiple ways to trim last two characters: substr , substring , replace or slice (cleanest solution).

 var array = ["517577144-2","503222534-2","100003527692828-2","654703438-2","4205501-2"]; // Using substr method var trimmed = array.map(function(item) { return item.substr(0,item.length - 2); }); log(trimmed); // Using substring method trimmed = array.map(function(item) { return item.substring(0,item.length - 2); }); log(trimmed); // Using regular expression in replace method trimmed = array.map(function(item) { return item.replace(/.{2}$/,''); }); log(trimmed); // Using slice method trimmed = array.map(function(item) { return item.slice(0,-2); }); log(trimmed); function log(array) { document.write('<pre>' + JSON.stringify(array, null, 2) + '</pre>'); } 

Instead of map you can always use a standard for loop too.

Answer 7

Using open source project jinqJs it would simply be

var result = jinqJs().from(array).select(function(row){return row.slice(0, row.length-2);});

See Fiddle