如何从具有可变文件名的查找中获取文件路径

Question

I have a command that works fine as is:

fname=$(find $dir -name '*001.txt')

What I would like to do is replace the number by a variable:

fname=$(find $dir -name '*$num.txt')

but get nothing. I have tried escaping the single quotes: \\'*$num.txt\\' , enclosing the single quotes in double quotes: "'"*$num.txt"'", but nothing works. What do I need?

Answer 1

尝试这个：

fname=$(find $dir -name "*${num}.txt")