静态Web服务中的Application / JSON是不受支持的媒体类型

Question

I am trying to create a restful-jersey webservice. I have to pass JSON object to the webservice.

    @POST
    @Path("/saveVehicleTrackingData")
    @Consumes(MediaType.APPLICATION_JSON)
    @Produces(MediaType.TEXT_PLAIN)
    public String saveVehicleTrackingData(VehicleTracking vehicleTracking) {
        return vehicleTracking.toString();
    }

When I try try to make request to the service, it says HTTP Status 415 - Unsupported Media Type. Please help. Also, what should be the type of single argument of the method saveVehicleTrackingData .

PS: I am using POSTMAN to make http request. http://goo.gl/vwXNXQ

UPDATE : As pointed out by peeskillet, the missing thing here is JSON Provider. The next challenge that I have is, how to integrate the JSON Provider in my project. After researching a little, I found FasterXML jackson as one of the JSON provider.

Answer 1

For your first question:

What kind of hosting (Tomcat, GlassFish or whatever...) are you using, and what is the Java version of the host? I know from experience that different version of Tomcat in combination with Jersey sometimes gives problems with @Consumes(MediaType.APPLICATION_JSON) .

About your second question:

You want to build a RESTful webservice, the right name for a path should be; VehicleTrackingData (or whatever you like). This path will work (request/response) with the known HTTP verbs; GET, POST, PUT or DELETE.

Answer 2

This image is just for reference. I just had it from another post.

Basically when you use raw , it will default to text/plain . The JSON in the drop down, is simply to select syntax highlighting. You still need to set the Content-Type header to application/json . You can click on the Headers button and add it.