[英]How to add a object to a sorted set that's within a hashmap of objects
I'm trying to add a passenger object into a sorted set. 我正在尝试将乘客对象添加到排序集中。 This sorted set is in a cruise object. 该排序的集合位于巡航对象中。 All of the cruise objects are within a hashMap. 所有的巡航对象都在hashMap中。 I'm kinda new to collections so I'm having trouble. 我是一个新手,所以遇到了麻烦。 This is my attempt to do what I'm doing. 这是我尝试做的事情。
HashMap<String, Cruise> cruiseMap = new HashMap<String, Cruise>();
SortedSet<Passenger> passengerSet = new TreeSet<Passenger>();
Queue<Passenger> waitingList = new LinkedList<Passenger>();
Cruise cruise = new Cruise("1", passengerSet, waitingList, false);
cruiseMap.put("1", cruise);
Passenger passenger = new Passenger("Smith", "J");
cruiseMap.get("1").getPassengerSet().add(passenger);
The passenger's parameters are strings that are last name then their first initial. 乘客的参数是字符串,字符串是姓氏,然后是他们的第一个名字首字母。 The cruise's parameters are as a string the date, the sortedSet passengers, there's a queue for waiting list and a boolean variable to determine if the ship has departed. 巡游的参数是日期字符串,sortedSet乘客,等待队列的队列和布尔值变量,以确定船只是否已出发。 I keep getting tons of errors when I run this code. 运行此代码时,我不断收到大量错误。 Thanks in advance for the help. 先谢谢您的帮助。
Here are the errors I'm recieving. 这是我收到的错误。
Exception in thread "main" java.lang.ClassCastException: edu.ilstu.Passenger cannot be cast to java.lang.Comparable
at java.util.TreeMap.compare(Unknown Source)
at java.util.TreeMap.put(Unknown Source)
at java.util.TreeSet.add(Unknown Source)
at edu.ilstu.Driver.main(Driver.java:48)
Passenger Class 旅客舱位
public class Passenger {
private String lastName = "";
private String firstName = "";
public Passenger()
{
lastName = "no last name yet";
firstName = "no first name yet";
}
public Passenger(String lastName, String firstName)
{
this.lastName = lastName;
this.firstName = firstName;
}
/**
* @return the lastName
*/
public String getLastName()
{
return lastName;
}
/**
* @param lastName the lastName to set
*/
public void setLastName(String lastName)
{
this.lastName = lastName;
}
/**
* @return the firstName
*/
public String getFirstName()
{
return firstName;
}
/**
* @param firstName the firstName to set
*/
public void setFirstName(String firstName)
{
this.firstName = firstName;
}
/* (non-Javadoc)
* @see java.lang.Object#toString()
*/
@Override
public String toString()
{
return lastName + " " + firstName;
}
}
Cruise Class 邮轮班
public class Cruise
{
private String day = "";
private SortedSet<Passenger> passengerSet = new TreeSet<Passenger>();
private Queue<Passenger> waitingList = new LinkedList<Passenger>();
private boolean hasDeparted = false;
public Cruise()
{
day = "no day yet";
passengerSet = null;
waitingList = null;
hasDeparted = false;
}
public Cruise(String day, SortedSet<Passenger> passengerSet, Queue<Passenger> waitingList, boolean hasDeparted)
{
this.day = day;
this.passengerSet = passengerSet;
this.waitingList = waitingList;
this.hasDeparted = hasDeparted;
}
/**
* @return the day
*/
public String getDay()
{
return day;
}
/**
* @param day the day to set
*/
public void setDay(String day)
{
this.day = day;
}
/**
* @return the passengerSet
*/
public SortedSet<Passenger> getPassengerSet()
{
return passengerSet;
}
/**
* @param passengerSet the passengerSet to set
*/
public void setPassengerSet(SortedSet<Passenger> passengerSet)
{
this.passengerSet = passengerSet;
}
/**
* @return the waitingList
*/
public Queue<Passenger> getWaitingList()
{
return waitingList;
}
/**
* @param waitingList the waitingList to set
*/
public void setWaitingList(Queue<Passenger> waitingList)
{
this.waitingList = waitingList;
}
/**
* @return the hasDeparted
*/
public boolean isHasDeparted()
{
return hasDeparted;
}
/**
* @param hasDeparted the hasDeparted to set
*/
public void setHasDeparted(boolean hasDeparted)
{
this.hasDeparted = hasDeparted;
}
}
It happens because your passengerSet
is TreeSet
( SortedSet
), which means it will sort itself after each adding, because TreeSet
is ordered set and has certain sequence unlike usual HashMap
. 发生这种情况的原因是您的passengerSet
是TreeSet
( SortedSet
),这意味着它将在每次添加后对其进行排序,因为TreeSet
是有序集合,并且具有不同于常规HashMap
特定顺序。 Every SortedMap
must know how to sort elements it contains. 每个SortedMap
必须知道如何对它包含的元素进行排序。 This can be done two ways: 这可以通过两种方式完成:
Comparable<T>
interface. 您可以从Comparable<T>
接口实现您的类。 Comparator<T>
to your SortedMap
. 您可以将自定义Comparator<T>
添加到SortedMap
。 So, you have three ways to fix it (may be more, but three of them - are obvious): 因此,您可以通过三种方式进行修复(可能更多,但其中三种很明显):
SortedMap
, let's say replace your SortedMap
to Map
and replace TreeMap
to HashMap
in your code. 摆脱SortedMap
,假设在代码中将SortedMap
替换为Map
并将TreeMap
替换为HashMap
。 Add custom comparator to your passengerSet
将自定义比较器添加到您的passengerSet
HashMap<String, Cruise> cruiseMap = new HashMap<String, Cruise>(); SortedSet<Passenger> passengerSet = new TreeSet<Passenger>(new Comparator<Passenger>() { @Override public int compare(Passenger lhs, Passenger rhs) { return lhs.getFirstName().compareTo(rhs.getFirstName()); } }); Queue<Passenger> waitingList = new LinkedList<>(); Cruise cruise = new Cruise("1", passengerSet, waitingList, false); cruiseMap.put("1", cruise); Passenger passenger = new Passenger("Smith", "J"); cruiseMap.get("1").getPassengerSet().add(passenger);
Implement the Comparable<T>
interface in your Passenger
class. 在Passenger
类中实现Comparable<T>
接口。
public class Passenger implements Comparable<Passenger> { private String lastName = ""; private String firstName = ""; public Passenger() { lastName = "no last name yet"; firstName = "no first name yet"; } public Passenger(String lastName, String firstName) { this.lastName = lastName; this.firstName = firstName; } /** * @return the lastName */ public String getLastName() { return lastName; } /** * @param lastName the lastName to set */ public void setLastName(String lastName) { this.lastName = lastName; } /** * @return the firstName */ public String getFirstName() { return firstName; } /** * @param firstName the firstName to set */ public void setFirstName(String firstName) { this.firstName = firstName; } /* (non-Javadoc) * @see java.lang.Object#toString() */ @Override public String toString() { return lastName + " " + firstName; } @Override public int compareTo(Passenger another) { return firstName.compareTo(another.firstName); } }
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