如何将名称列表实现为预制类？

Question

I have a class called Name that takes first and last name with few basic functions:

class Name:

def __init__(self, first, last):
    self._first = first
    self._last = last

def first(self):
    return self._first

def last(self):
    return self._last

def __repre__(self):
    print("{} {}".format(self._first, self._last))

Now I need to create a function that takes a list that returns a list of Name objects. Text_file is just a text file that has names line by line with a space between first and last name.

def name_list(text_file):

  with open(text_file) as f:
      lines = f.read().splitlines()
      for name in lines:
          print(lines)

I realize I've only taken the list and returned the names in the list, not a list as Name objects.

How do I use my class to return a list of name objects?

Answer 1

def name_list(text_file):
    file = open(text_file, 'r')
    list = []
    for line in file:
        first, last = line.split()
        list.append(Name(first, last))
    return list

This will loop through each line, break it up on the space, create a name object, add it to the list, then return the list.

Then to print it out do something like:

list = name_list(file)
for name in list:
    print('Name: {0} {1}'.format(name._first, name._last))

Answer 2

The simplest is just to split each line on white space. You've got some redundant stuff in the above: you can simply iterate on a file to go line by line in it -- no need to call readlines.

def name_list(text_file):
    names = []
    with open(text_file) as f:
        for line in f:
             first_name, last_name in line.split(' ')  # tuple unpacking
             names.append(Name(first_name, last_name))
    return names

Answer 3

Thought it might be cool to show how to do this as a one-liner in Python. I understand it might be a bit less-readable to newcomers and, therefore, probably shouldn't be the accepted answer, but worth knowing:

>>> names = [Name(*line.split()) for line in open(text_file)]

Basically, we iterate through each line in the text file, splitting on whitespace, then we use the * -operator to unpack the values as positional arguments to the class.

Answer 4

One more possible solution:

name_objects = list()
with open(text_file) as f:
      for each_line in f:
          name_objects.append(Name(each_line.split()))