XSL中的特殊字符
[英]Special characters in XSL
问题描述
I'm working on a XSL 1.0 transformation to get HTML visualisation when displaying the XML in Firefox. 
我正在进行XSL 1.0转换，以便在Firefox中显示XML时获得HTML可视化。 In my original XML, I have characters like 在我的原始XML中，我有类似
é è ‘...
I need to convert them into 我需要将它们转换为
é, è, ‘...
I have used this template : 我已经使用了这个模板：
<xsl:template name="string-replace-all">
<xsl:param name="text" />
<xsl:param name="replace" />
<xsl:param name="by" />
<xsl:choose>
<xsl:when test="contains($text, $replace)">
<xsl:value-of select="substring-before($text,$replace)" />
<xsl:value-of select="$by" />
<xsl:call-template name="string-replace-all">
<xsl:with-param name="text" select="substring-after($text,$replace)" />
<xsl:with-param name="replace" select="$replace" />
<xsl:with-param name="by" select="$by" />
</xsl:call-template>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="$text" />
</xsl:otherwise>
</xsl:choose>
Calling for each special character (here for example è) : 要求每个特殊字符（例如＆egrave;）：
<xsl:variable name="newtext">
<xsl:call-template name="string-replace-all">
<xsl:with-param name="text" select="$originaltext" />
<xsl:with-param name="replace" select="'&egrave;'" />
<xsl:with-param name="by" select="'è'" />
</xsl:call-template>
</xsl:variable>
Is there a solution where I can directly replace & 有没有可以直接替换&的解决方案& into & for example without the need to call the replacement template for each special character I expect to exist? 进入＆例如不需要为我希望存在的每个特殊字符调用替换模板？
3 个解决方案
解决方案1
1 2015-04-07 11:03:45
Is there a solution where I can directly replace & into & for example without the need to call the replacement template for each special character I expect to exist?
Why don't you simply disable the escaping when outputting the text? 为什么在输出文本时不简单地禁用转义？ For example, given an input of: 例如，输入以下内容：
<content>Lor&eacute;m ipsum &lsquo;dolor&lsquo; sit am&egrave;t, consectetuer adipiscing elit.</content>
you can have your stylesheet process this as: 您可以让样式表将其处理为：
<p>
<xsl:value-of select="content" disable-output-escaping="yes"/>
</p>
and return: 然后返回：
<p>Lorém ipsum ‘dolor‘ sit amèt, consectetuer adipiscing elit.</p>
which a browser should render as: 浏览器应将其呈现为：
解决方案2
1 已采纳 2015-04-07 15:40:48
This seems to work for me in (an old version of) Firefox: 在Firefox（旧版本）中，这似乎对我有用：
XML XML格式
<?xml version="1.0" encoding="utf-8"?>
<?xml-stylesheet type="text/xsl" href="mystyle.xsl"?>
<root>
<description>Article Containing Escaped Entitites</description>
<content>Lor&eacute;m ipsum &lsquo;dolor&lsquo; sit am&egrave;t, consectetuer adipiscing elit.</content>
</root>
mystyle.xsl mystyle.xsl
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/root">
<html>
<body>
<h2><xsl:value-of select="description"/></h2>
<p id="content">
<xsl:value-of select="content"/>
</p>
<script>
var element = document.getElementById("content");
element.innerHTML = element.innerHTML.replace(/&amp;/g,'&');
</script>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
Result (screenshot): 结果（屏幕截图）：
Caveat : I am not a Javascript expert; 警告 ：我不是Java语言专家；我不是Java语言专家。 this is just something I cobbled together on impulse. 这只是我一时冲动而拼凑的东西。
解决方案3
-2 2015-04-07 08:31:44
String htmlstring = "Put Your HTML string here"
+ htmlstringbuf
.toString()
.replaceAll(" ", " ")
.replaceAll("&", "&")
.replaceAll("null", " ")
.replaceAll("<\\?xml version=\"1.0\" encoding=\"UTF-8\"\\?>"," ")
.replaceAll("Â", "<br></br>")
.replaceAll("<\\?xml version = '1.0' encoding ='UTF-8'\\?>",
" ") + "</body>";
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