使用java 8迭代和过滤两个列表

Question

I want to iterate two lists and get new filtered list which will have values not present in second list. Can anyone help?

I have two lists - one is list of strings, and the other is list of MyClass objects.

List<String> list1;
List<MyClass> list2;

MyClass {

    MyClass(String val)
    {
        this.str = val;
    }

     String str;
     ...
     ...
}

I want filtered list of strings based on -> check second list for elements (abc) whose values not present in list1 .

List<String> list1 = Arrays.asList("abc", "xyz", "lmn");

List<MyClass> list2 = new ArrayList<MyClass>();

MyClass obj = new MyClass("abc");
list2.add(obj);
obj = new MyClass("xyz");
list2.add(obj);

Now I want new filtered list -> which will have value => "lmn". ie values not present in list2 whose elements are in list1 .

Answer 1

// produce the filter set by streaming the items from list 2
// assume list2 has elements of type MyClass where getStr gets the
// string that might appear in list1
Set<String> unavailableItems = list2.stream()
    .map(MyClass::getStr)
    .collect(Collectors.toSet());

// stream the list and use the set to filter it
List<String> unavailable = list1.stream()
            .filter(e -> unavailableItems.contains(e))
            .collect(Collectors.toList());

Answer 2

this can be achieved using below...

 List<String> unavailable = list1.stream()
                            .filter(e -> !list2.contains(e))
                            .collect(Collectors.toList());

Answer 3

Doing it with streams is easy and readable:

Predicate<String> notIn2 = s -> list2.stream().noneMatch(mc -> s.equals(mc.str));
List<String> list3 = list1.stream().filter(notIn2).collect(Collectors.toList());

Answer 4

If you stream the first list and use a filter based on contains within the second...

list1.stream()
    .filter(item -> !list2.contains(item))

The next question is what code you'll add to the end of this streaming operation to further process the results... over to you.

Also, list.contains is quite slow, so you would be better with sets.

But then if you're using sets, you might find some easier operations to handle this, like removeAll

Set list1 = ...;
Set list2 = ...;
Set target = new Set();
target.addAll(list1);
target.removeAll(list2);

Given we don't know how you're going to use this, it's not really possible to advise which approach to take.

Answer 5

See below, would welcome anyones feedback on the below code.

not common between two arrays:

List<String> l3 =list1.stream().filter(x -> !list2.contains(x)).collect(Collectors.toList());

Common between two arrays:

List<String> l3 =list1.stream().filter(x -> list2.contains(x)).collect(Collectors.toList());

Answer 6

list1 = list1.stream().filter(str1-> 
        list2.stream().map(x->x.getStr()).collect(Collectors.toSet())
        .contains(str1)).collect(Collectors.toList());

This may work more efficient.

Answer 7

if you have class with id and you want to filter by id

line1 : you mape all the id

line2: filter what is not exist in the map

Set<String> mapId = entityResponse.getEntities().stream().map(Entity::getId).collect(Collectors.toSet());

List<String> entityNotExist = entityValues.stream().filter(n -> !mapId.contains(n.getId())).map(DTOEntity::getId).collect(Collectors.toList());

Answer 8

@DSchmdit answer worked for me. I would like to add on that. So my requirement was to filter a file based on some configurations stored in the table. The file is first retrieved and collected as list of dtos. I receive the configurations from the db and store it as another list. This is how I made the filtering work with streams

    List<FPRSDeferralModel> modelList = Files
            .lines(Paths.get("src/main/resources/rootFiles/XXXXX.txt")).parallel().parallel()
            .map(line -> {
                FileModel fileModel= new FileModel();
                line = line.trim();
                if (line != null && !line.isEmpty()) {
                    System.out.println("line" + line);
                    fileModel.setPlanId(Long.parseLong(line.substring(0, 5)));
                    fileModel.setDivisionList(line.substring(15, 30));
                    fileModel.setRegionList(line.substring(31, 50));
                    Map<String, String> newMap = new HashedMap<>();
                    newMap.put("other", line.substring(51, 80));
                    fileModel.setOtherDetailsMap(newMap);

                }
                return fileModel;
            }).collect(Collectors.toList());

    for (FileModel model : modelList) {
        System.out.println("model:" + model);
    }

    DbConfigModelList respList = populate();
    System.out.println("after populate");
    List<DbConfig> respModelList = respList.getFeedbackResponseList();


    Predicate<FileModel> somePre = s -> respModelList.stream().anyMatch(respitem -> {

        System.out.println("sinde respitem:"+respitem.getPrimaryConfig().getPlanId());
        System.out.println("s.getPlanid()"+s.getPlanId());
        System.out.println("s.getPlanId() == respitem.getPrimaryConfig().getPlanId():"+
        (s.getPlanId().compareTo(respitem.getPrimaryConfig().getPlanId())));
        return s.getPlanId().compareTo(respitem.getPrimaryConfig().getPlanId()) == 0
                && (s.getSsnId() != null);
    });



 final List<FileModel> finalList =  modelList.stream().parallel().filter(somePre).collect(Collectors.toList());

 finalList.stream().forEach(item -> {
     System.out.println("filtered item is:"+item);
 });

The details are in the implementation of filter predicates. This proves much more perfomant over iterating over loops and filtering out

Answer 9

`List<String> unavailable = list1.stream()
                .filter(e -> (list2.stream()
                        .filter(d -> d.getStr().equals(e))
                        .count())<1)
                        .collect(Collectors.toList());`
for this if i change to 
`List<String> unavailable = list1.stream()
                .filter(e -> (list2.stream()
                        .filter(d -> d.getStr().equals(e))
                        .count())>0)
                        .collect(Collectors.toList());`
will it give me list1 matched with list2 right?