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Laravel Blade:从父视图访问嵌套部分中的变量

[英]Laravel Blade: Getting access to a variable in a nested partial from a parent view

My parent view looks like this: 我的父视图如下所示:
show.blade.php show.blade.php

@include('inquiries.partials.inquiries')

It uses the following partial: 它使用以下部分:
inquiries.blade.php inquiries.blade.php

<ul>
    @foreach($inquiry as $key => $item)
        <li>
            @include('inquiries.partials.inquiry')
        </li>
    @endforeach
</ul>

Which uses another partial: 其中使用另一部分:
inquiry.blade.php inquiry.blade.php

<div class="row">
    <div class="col-xs-10">
        <div class="data"> ... </div>
    </div>
    <div class="col-xs-2 text-right">
         @yield('inquiry.toolbar', '')
    </div>
</div>

In show.blade.php I want to define inquiry.toolbar section for inquiry.blade.php , however I need to access $key variable from inquiries.blade.php file, like so: show.blade.php我想定义为inquiry.toolbar部分inquiry.blade.php但是我需要从inquiries.blade.php文件访问$关键变量,就像这样:

@include('inquiries.partials.inquiries')

@section('inquiry.toolbar')
{!! button_delete([
    'route' => ['inquiries.items.destroy', $key]
]) !!}
@stop

However, the code above does not work (I get "Undefined variable: key"). 但是,上面的代码不起作用(我得到“Undefined variable:key”)。
Is it possible? 可能吗?

You can pass data when including a view, like so: 您可以在包含视图时传递数据,如下所示:

<ul>
    @foreach($inquiry as $key => $item)
        <li>
            @include('inquiries.partials.inquiry', compact('key'))
        </li>
    @endforeach
</ul>

And it will be available on your view. 它将在您的视图中提供。

Check the docs for more information. 查看文档以获取更多信息。

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