将多种表单数据传递给PHP控制器

Question

$('#save').on("click", function() {
      //collect the form data while iterating over the inputs
      var data = [];
      $('[name=form]').find('input, select, textarea').each(function() {
        if ($(this).attr('value') != '') {
          var name = $(this).attr('name');
          var value = $(this).attr('value');
          data[name] = value;
        }
      })
      for (var i = 1, ii = form.length; i < ii; i++) {
        var name = 'form' + i;
        $('[name=' + name + ']').find('input, textarea').each(function() {
          data[i] = [];
          if ($(this).attr('value') != '') {
            var name = $(this).attr('name');
            var value = $(this).attr('value');
            data[i][name] = value;
          }
        })
      }
      $.post('foo', data,
          function(data) {
            console.log(data);

I have the above jquery code where I wish to post multiple form data into my PHP backend controller.

In my controller, I used

 $input = Input::all()

Question 1

How do I access the data in the array that I have passed? Let's say I have foo input and bar input in my form. I tried to use

$input['foo']
$input['bar']

but I'm getting internal server error with undefined index error.

Question 2

How do I access the data of the data[i][name]? Let's say I have form1, form2, form3, so it my data array will become

$data[1][foo]
$data[2][foo]
$data[3][foo]

How can I access these in my PHP controller?

Thanks and sorry for the long question

Answer 1

with FormData object.

var formdata = new FormData();
formdata.append("name", value);

on server-side you read values like this:

$name = $_POST["name"];