删除电子邮件模式，使用grep，awk或sed保留其余模式？

Question

I got this plain text from wich I want to delete all email adresses (or replace by E). I want to keep everything else in the text file. The email adresses can be followed by a space, colon, semicolon, question or exclamation mark. I work with gnuwin and tried grep but didn't got the right result

grep -Eiv "\b[A-Z0-9._%+-]+@[A-Z0-9.-]+\.[A-Z]{2,4}\b" in.txt > out.txt

This removes every line containing the email pattern. I want only the emails gone.

thank you

Answer 1

对于替换使用sed而不是grep ：

sed -r 's/\b[A-Z0-9._%+-]+@[A-Z0-9.-]+\.[A-Z]{2,4}\b//Ig' in.txt > out.txt

Answer 2

Combining both answers (frhd and anubhava) I get the code I wan't.

sed -r "s/([A-Za-z0-9._%+-]+@[A-Za-z0-9.-]+\.[A-Za-z]{2,4})//g" in.txt > out.txt

It removes every email from the text file

Answer 3

Regex version:

([a-zA-Z0-9\._%+-]+@[a-zA-Z0-9\.-]+\.[a-zA-Z]{2,4})[\ \:\;\?\!]?

https://regex101.com/r/qJ2eG7/1