[英]how to sum a list of arguments with recursion?
I am trying to write a function that takes any number of arguments and then sums them using recursion ( I am not using the built in sum function. I am assuming arguments will be int. ) 我试图编写一个函数,该函数接受任意数量的参数,然后使用递归求和(我未使用内置的sum函数。我假设参数将为int。)
But my base case doesn't stop it from recursing! 但是我的基本情况并不能阻止它再次发生! Any hints?
有什么提示吗?
def sum_all(*args):
if args == ():
return 0
else:
return args[0] + sum_all(args[1:])
You need to expand the args in your recursion, and not args
would be sufficient for the test: 您需要在递归中扩展args,而
not args
不足以进行测试:
def sum_all(*args):
if not args:
return 0
return args[0] + sum_all(*args[1:])
^
Python 3 also added some new syntax that allows you to unpack *args
, eg: Python 3还添加了一些新语法,使您可以解压缩
*args
,例如:
def sum_all(*args):
if not args:
return 0
a, *b = args
return a + sum_all(*b)
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