从（“ \\ n”）换行符获取字符串

Question

I have an arraylist that containing string like abc"\\n"1234,cde"\\n"567 fgh"\\n"890. I want to get string from where it found new line. like from this array i want only 1234,567 and 890. here is what am doing. but it says "Incompatible Types" Thanks actually i have show the dialog that containing these contacts.and than if user click on any contacts it opens the dialer activity.

 for(String contact: manycontacts){
        String contacts=contact.split("\\r?\\n");
    }

Answer 1

split returns a String[] not a String

for(String contact: manycontacts){
    String[] contacts=contact.split("\\r?\\n");
}

If you need it as one string you have to iterate over the array and concatinate the strings. or use commons-utils from apache to join it.

Answer 2

split method returns an array of strings String[] . In your code, you're returning a simply String. That is the incompatibility.

Simple change it to:

 for(String contact: manycontacts){
        String[] contacts=contact.split("\\r?\\n");
 }

Answer 3

The split function returns an array of Strings, but you are trying to assign an array of strings to a single string, which throws this error. Rather use:

for(String contact: manycontacts){
    String[] contacts=contact.split("\\r?\\n");
    for(String split : contacts) {
       //here you can go on and workt with a single splittet value
    }
}

Answer 4

contact.split() is returning a String array, not a String, hence the type is incompatible. You'll need

String[] contacts = contact.split("\\r?\\n");

Answer 5

这是因为split返回的String数组将为String []。

Answer 6

简单地我用this.trim调整字符串。

 String numberonly = contacts.substring(contact.indexOf('\n'));