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将子类型转换为超类型

[英]Convert sub-type to super-type

I have a abstract super class A, and a subclass B that extends this class. 我有一个抽象的超类A和一个扩展该类的子类B。

public abstract class A {

}

public class B extends A {


}

I have a method that returns type A, but object B 我有一个返回类型A但对象B的方法

public A fetchType() {
    A a = new B();
    return a;

}

When I call the fetchType method, I want to actually get object A. In this case, I might have to cast B to A so I get A. Can someone please advise how do I do that? 当我调用fetchType方法时,实际上要获取对象A。在这种情况下,我可能必须将B强制转换为A,这样我才能得到A。有人可以建议我该怎么做吗?

You cannot create an object if the type is abstract. 如果类型是抽象的,则不能创建对象。

Here class A is abstract class, which means you will NEVER be able to create object A . 这里的类A是抽象类,这意味着您将永远无法创建对象A

This is not allowed: A a = new A(); 这是不允许的: A a = new A();

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