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在同一打开的窗口中的python打印命令不在提示符下

[英]python print command in same open window not in prompt

Ok so i am trying my hand in python and ran into a issue with this little app i am trying to put together. 好的,所以我尝试使用python并遇到我试图组合的这个小应用程序的问题。 I am trying to have a window open on run and ask for a keyword input, then match that input to a any line in a file. 我试图在运行时打开一个窗口,并要求输入关键字,然后将该输入与文件中的任何行匹配。 I enter the input and press show, but the results don't show or show in the prompt. 我输入了输入并按显示,但结果未显示或未在提示中显示。 I need to have the results show in the open window. 我需要在打开的窗口中显示结果。 possibly on a new row and column that is created when the show button is pressed. 可能在按下显示按钮时创建的新行和新列上。 so the results show in the window only, I am on a ubuntu based system. 因此结果仅显示在窗口中,我在基于ubuntu的系统上。 Here is my app .py file 这是我的应用程序.py文件

#!/usr/bin/python
# -*- coding: utf-8 -*-

# sets the name settings
from Tkinter import *
class App(Frame):
def __init__(self, master=None):
    Frame.__init__(self, master)
    self.pack()

# runs the script to get full 
# list of programs for matching
#subprocess.call(["listcmnd.sh"])

# create the application
myapp = App()

# sets the e1 variable
e1 = Entry(myapp)

# checks keyword agianst 
# programs in the sam.txt file
import re

keyword = open("results/program_files/sam.txt", "r")

for line in keyword:
if re.match("str(text)", line):
    print line,

# prints results of keyword entry match
def show_entry_fields():
print("Program Name: %s" % (e1.get()))

# gives the output of findings
from Tkinter import *

# asks for search critiria
text = Label(myapp, text="Keyword: ").grid(row=0)

# displays the buttons for getting 
# results and closing program
Button(myapp, text='Quit', command=myapp.quit).grid(row=3, column=0,     sticky=W, pady=4)
Button(myapp, text='Show', command=show_entry_fields).grid(row=3, column=1, sticky=W, pady=4)

# prints results of keyword entry match
def show_entry_fields():
print("Program Name: %s" % (e1.get()))

# displays the text entry field
e1.grid(row=0, column=1)

#
# here are method calls to the window manager class
#
myapp.master.title("Program Search Tool")
myapp.master.maxsize(1000, 400)

# start the program
myapp.mainloop()

ok so i made a few alterations to the main script but still outputs results to terminal and not in the open window 好的,所以我对主脚本进行了一些更改,但仍将结果输出到终端,而不是在打开的窗口中

Here is new code alterations 这是新的代码更改

  #!/usr/bin/python
  # -*- coding: utf-8 -*-

  # sets the name settings
  from Tkinter import *
  class App(Frame):
      def __init__(self, master=None):
         Frame.__init__(self, master)
          self.pack()

  # runs the script to get full 
  # list of programs for matching
  #subprocess.call(["listcmnd.sh"])

  # create the application
  myapp = App()

  # sets the e1 variable
  e1 = Entry(myapp)

  # checks keyword agianst 
  # programs in the sam.txt file
  import re

  keyword = open("results/program_files/sam.txt", "r")

  for line in keyword:
    if re.match("get()(text)", line):
          print line,

  # prints results of keyword entry match
  def show_entry_fields():
    print("Program Name: %s" % (e1.get()))

  # asks for search critiria
  # displays the text entry field
  e1.grid(row=0, column=1)
  text = Label(myapp, text="Program Name: ")
  text.grid(row=3, column=0)

  # displays the buttons for getting 
  # results and closing program
  Button(myapp, text='Quit', command=myapp.quit).grid(row=4, column=0, sticky=W, pady=4)
  Button(myapp, text='Show', command=show_entry_fields).grid(row=2, column=0, sticky=W, pady=4)

  #
  # here are method calls to the window manager class
  #
  myapp.master.title("Program Search Tool")
  myapp.master.maxsize(1000, 1000)
  myapp.master.minsize(50, 50)

  # start the program
  myapp.mainloop()

What you should do is create a label (or maybe create it before and update it) in function 您应该做的是在函数中创建一个标签(或者可能在之前创建并更新它)

def show_entry_fields():

Additional remarks: 附加说明:

you import Tkinter several times 您多次导入Tkinter

you also define def show_entry_fields(): twice 您还定义了def show_entry_fields():两次

text = Label(myapp, text="Keyword: ").grid(row=0)

doesn't work. 不起作用。 You must write: 您必须写:

 text = Label(myapp, text="Keyword: ")
 text.grid(row=0)

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