获取调用函数的类的名称

Question

Context

I'm writting a debug class in Qt for a project and I want to know in which class I am so now I write:

MyClass::function1()
{
   DEBUG_IN("[MyClass] Enters function1()")
   ....do something
   DEBUG_OUT("[MyClass] Exits function1()");
}

EDIT: DEBUG_IN() and DEBUG_OUT() are global functions. They are not part of the class MyClass

The question

Is it possible to get the name of the class where DEBUG() is called?

(and the bame of the function where DEBUG() is called?)

so that I could just do:

MyClass::function1()
{
   DEBUG_IN("function1()")
   ....do something
   DEBUG_OUT("function1()");
}

and

DEBUG_IN(QString text)
{
   qDebug() << qPrintable("[")
            << qPrintable(getClassName())
            << qPrintable("] Enters ")
            << qPrintable(text);
}

Thx a lot

Answer 1

The closest to what you want would be __PRETTY_FUNCTION__ . This includes fully qualified function name and signature.

Edit:

You should use it like this:

#define DEBUG_IN_PRETTY(...) DEBUG_IN(__PRETTY_FUNCTION__, __VA_ARGS__)

then call DEBUG_IN_PRETTY (obviously DEBUG_IN needs to take the extra argument). This will expand the macro at the call site.

Answer 2

Indeed there is.

typeid(*this).name()

Will give you a readable classname. It is not specified how this name is constructed so your compiler might not give the exact class name, but it should be good for debugging purposes.

As DEBUG_IN and DEBUG_OUT are free functions you need to pass the class type as an argument. A simple template should do the trick

template<typename CLASSNAME>
void DEBUG_IN(QString msg, CLASSNAME* that)
{
   ...  typeid(*that).name()

}