[英]Prefix Expression evaluating incorrectly - Java
private class InputListener implements ActionListener
{
public void actionPerformed(ActionEvent e)
{
// Create an integer and character stack
Stack<Integer> operandStack = new Stack<Integer>();
Stack<Character> operatorStack = new Stack<Character>();
// User input in input text field
String input = inputTextField.getText();
// Create string tokenizer containing string input
StringTokenizer strToken = new StringTokenizer(input);
// Loop while there are tokens
while (strToken.hasMoreTokens())
{
String i = strToken.nextToken();
int operand;
char operator;
try
{
operand = Integer.parseInt(i);
operandStack.push(operand);
}
catch (NumberFormatException nfe)
{
operator = i.charAt(0);
operatorStack.push(operator);
}
}
// Loop until there is only one item left in the
// operandStack. This one item left is the result
while(operandStack.size() > 1)
{
// Perform the operations on the stack
// and push the result back onto the operandStack
operandStack.push(operate(operandStack.pop(),
operandStack.pop(), operatorStack.pop()));
}
// Display the result as a string in the result text field
resultTextField.setText(Integer.toString(operandStack.peek()));
}
// Sum and product computed
public int operate(Integer operand1, Integer operand2, char operator)
{
switch(operator)
{
case '*':
return operand2 * operand1;
case '/':
return operand2 / operand1;
case '%':
return operand2 % operand1;
case '+':
return operand2 + operand1;
case '-':
return operand2 - operand1;
default:
throw new IllegalStateException("Unknown operator " + operator + " ");
}
}
}
The prefix expression code provided is incorrectly evaluating expressions with more than one operator. 提供的前缀表达式代码使用多个运算符错误地评估了表达式。 The expression:
* + 16 4 + 3 1
should evaluate to 80 = ((16 + 4) * (3 + 1))
, but instead it evaluates to 128
, which I think is evaluating as: ((16 + 4) * (3 + 1) + (16 * 3))
. 表达式:
* + 16 4 + 3 1
应该计算为80 = ((16 + 4) * (3 + 1))
,但是它的计算结果为128
,我认为计算结果为: ((16 + 4) * (3 + 1) + (16 * 3))
。 How do I edit the code to correct this problem? 如何编辑代码以更正此问题? Thank you for your help.
谢谢您的帮助。
In prefix evaluation,Important thing to remember is 在前缀评估中,要记住的重要事项是
operand 1= pop(); 操作数1 = pop();
operand 2= pop(); 操作数2 = pop();
and say the operator is - 说经营者是-
The value that is pushed is operand 1 - operand 2 and not operand 2 - operand 1 推入的值是操作数1-操作数2而不是操作数2-操作数1
But something else is causing * + 16 4 + 3 1 to evaluate to 128. 但是其他原因导致* + 16 4 + 3 1的计算结果为128。
I used the following algo for evaluating in java and it works fine 我使用以下算法在Java中进行评估,效果很好
1.Take the prefix expression as a string in a variable with characters separated by single space. 1.将前缀表达式作为字符串包含在变量中,字符之间用单个空格分隔。
2.Traverse the string from index length-1 to 0 2.将字符串从索引长度1遍历到0
3.If its a number, perform push ,and if its a multidigit number,first obtain the full number and then push it 3.如果是数字,则执行压入;如果是数字,则先获取完整的数字,然后再压入
4.If its an operator then simply do the thing which i mentioned in beginning of the answer. 4.如果是操作员,则只需做我在答案开头提到的事情即可。
It is a simple code. 这是一个简单的代码。
import java.io.*;
import java.util.*;
class PREFIXEVAL
{
public static void main(String []args)throws IOException
{
String p,n="";StringBuffer b;int i,op1,op2;char c;Stack<Integer> s=new Stack<Integer>();
BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
System.out.println("enter the prefix expression separated by spaces");
p=br.readLine();
i=p.length()-1;
while(i>=0)
{
c=p.charAt(i);
if(c>=48&&c<=57)
n=n+c;
else if(c==' '&&!n.equals(""))
{/*handles both single and multidigit numbers*/
b=new StringBuffer(n);b.reverse();n=b.toString();
s.push(Integer.parseInt(n));n="";
}
else
{
if(c=='+')
{
op1=s.pop();
op2=s.pop();
s.push(op1+op2);
}
else if(c=='-')
{
op1=s.pop();
op2=s.pop();
s.push(op1-op2);
}
else if(c=='*')
{
op1=s.pop();
op2=s.pop();
s.push(op1*op2);
}
else if(c=='%')
{
op1=s.pop();
op2=s.pop();
s.push(op1%op2);
}
else if(c=='/')
{
op1=s.pop();
op2=s.pop();
s.push(op1/op2);
}
}
i--;
}
System.out.println("the prefix expression evaluates to "+s.peek());
}
}
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